I think any irrational number would do this? I'm not positive though. Some examples may be pi or the square root of 2.
Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
Answer:
1/4
Step-by-step explanation:
15/60 = 1/4
Yea you got this the answer is easy
Hey there mate!
Your correct answer would be
![\left[\begin{array}{ccc}\boxed{\boxed{ 4/6 = 6/9}}\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B%204%2F6%20%3D%206%2F9%7D%7D%5Cend%7Barray%7D%5Cright%5D%20)
This would be because 4/6 is almost 1 as a whole, and also, 6/9 is almost 1, as a whole, so this would totally make sense for this to be a proportional.
Hope this helps you budd!