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3 years ago

What is 7 over 8k =35

Mathematics

1 answer:

RUDIKE [14]3 years ago

5 0

Answer:

Step-by-step explanation:

k=40

hope it helps

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Create a 3rd degree polynomial function with one zero at three. Sketch a graph

DedPeter [7]

Answer:

$f(x) = {x}^{3} - 9 {x}^{2} + 27x - 27$

Step-by-step explanation:

We want to create a third degree polynomial function with one zero at three.

In other words, we want to find a polynomial function with roots x=3 , multiplicity, 3.

Since x=3 is a solution, x-3 is the only factor that repeats thrice.

$f(x) = {(x - 3)}^{3}$

We expand to get:

$f(x) = x( {x}^{2} - 6x + 9) - 3( {x}^{2} - 6x + 9)$

$f(x) = {x}^{3} - 6 {x}^{2} + 9x- 3 {x}^{2} + 18x - 27$

This simplifies to:

$f(x) = {x}^{3} - 9 {x}^{2} + 27x - 27$

See attachment for graph.

4 0

3 years ago

65÷5=____ with ____ left over

Molodets [167]

65 ÷ 5 = 11 with 0 left over

Hope this helps! ;)

7 0

3 years ago

Waht is the value of ((2/3)^0)^-3

mestny [16]

Answer:

$\left(\left(\frac{2}{3}\right)^0\right)^{-3}=1$

Step-by-step explanation:

$\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0\\\left(\left(\frac{2}{3}\right)^0\right)^{-3}=\left(\frac{2}{3}\right)^{0\cdot \left(-3\right)}\\=\left(\frac{2}{3}\right)^0\\=1$

Red

6 0

3 years ago

1/2r + 2 (3/4r - 1) = 1/4r + 6<br><br>

gtnhenbr [62]

Answer:

r=32/7

Step-by-step explanation:

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3 years ago

Read 2 more answers

421.2 - 305.8<br> Using mental math

Nitella [24]

Answer:

114.4

Step-by-step explanation:

421.2

-305.2

114.4

8 0

3 years ago