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2 years ago

Put the operations to simplify the expression in the correct order.

Mathematics

1 answer:

4vir4ik [10]2 years ago

6 0

Answer:

Step-by-step explanation:

First multiply 5*9=45

Next subtract 15=30

Then Add 82 to 30=112

Last subtract 70 from 112=42

SO you get 42

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X-3<-12 Choose the correct graph for the inequality?

olga55 [171]

The correct graph is the last one
x -3<-12
x<-12+3
x<-9

7 0

3 years ago

For the following hypothesis test, determine the null and alternative hypotheses. Also, classify the hypothesis test as two-tail

bagirrra123 [75]

Answer:

Option B:

$H_0: \mu = 22.1$

$H_a: \mu \neq 22.1$

Classification:

The hypothesis test is Two-tailed.

Step-by-step explanation:

The mean length of imprisonment for motor-vehicle theft offenders in this country is 22.1 months.

This means that the null hypothesis is that the mean is of 22.1 months, that is:

$H_0: \mu = 22.1$

A hypothesis test is to be performed to determine whether the mean length of imprisonment for motor-vehicle theft offenders in this city differs from the national mean of 22.1 months.

At the alternate hypothesis, we test if this mean is different of 22.1, that is:

$H_a: \mu \neq 22.1$

Which means that the answer is given by option b).

Which of the following is the correct classification of the hypothesis test?

We test if the mean is different from a value, which means that the hypothesis test is Two-tailed.

7 0

3 years ago

liz wants to determine which sport students like to play the most at her school.which method will most likely produce a random e

never [62]

Answer:

Random sampling

Step-by-step explanation:

Random sampling is a method of choosing a sample of observations from a population to make assumptions about the population. It is also called probability sampling.

6 0

2 years ago

Please help fast......

Tom [10]

$\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\ 1.AY=BX&\text{1. Given}\\ 2.AB \cong AB&\text{2. Reflexive Property}\\ 3. AD || BC&\text{3. Property of a square}\\ 4. \angle ABE \cong \angle AXB&\text{4. Alternate Interior Angles}\\ 5. \angle BAY \cong \angle BYA&\text{5. Alternate Interior Angles}\\6. \triangle BAX \cong \triangle ABY&\text{6. Angle-Side-Angle Theorem}\\ 7. AX \cong BY&\text{7. CPCTC}\\\end{array}$

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$\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. AB=CF&\text{1. Given}\\2.AB+BF=A'F&\text{2. Segment Addition Postulate}\\3.CF+BF=A'F&\text{3. Substitution Property}\\4.CF+BF+BC&\text{4. Segment Addition Postulate}\\5.A'F=BC&\text{5. Transitive Property}\\6. \angle AFE = \angle DBC&\text{6. Given}\\7. EF = BD&\text{7. Given}\\8. \triangle AFE \cong \triangle CBD&\text{8. Side-Angle-Side Theorem}\\\end{array}$

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$\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\\text{1.AC bisects }\angle BAD&\text{1. Given}\\2. \angle BAC \cong \angle DAC&\text{2. Property of angle bisector}\\3.AC = AC&\text{3. Reflexive Property}&4. \angle ACB \cong \angle ACD&\text{4. Property of angle bisector}\\5. \triangle ABC \cong \triangle ADC&\text{5. Angle-Side-Angle Theorem}\\6.BC=CD&\text{6. CPCTC}\\\end{array}$

5 0

3 years ago

The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.3 days and a standard de

inna [77]

Answer:

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Step-by-step explanation:

Step(i):-

Given mean of the Population μ = 5.3 days

Given standard deviation of the population 'σ' = 2 days

Let 'X' be the random variable in normal distribution

Let x₁ = 4

$Z_{1} = \frac{x_{1}-mean }{S.D} = \frac{4-5.3}{2} = -0.65$

Let x₂ = 7

$Z_{2} = \frac{x_{2}-mean }{S.D} = \frac{7-5.3}{2} = 0.85$

Step(ii):-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = P(-0.65≤Z≤0.85)

= P(Z≤0.85) - P(Z≤-0.65)

= 0.5 + A( 0.85) - ( 0.5 - A(-0.65)

= 0.5 + A( 0.85) - 0.5 +A(0.65) ( ∵A(-0.65) = A(0.65)

= A(0.85) + A(0.65)

= 0.3023 + 0.2422

= 0.5445

Final answer:-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

6 0

3 years ago