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Art [367]
3 years ago
6

How can the area of a rectangle be found using multiplication?

Mathematics
2 answers:
mr Goodwill [35]3 years ago
5 0
The area of a rectangle is length times width
larisa [96]3 years ago
3 0
The length times the width
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What is the name of the line of reflection for the pair of figures? Enter your answer in the box. line
statuscvo [17]

Are you asking for the letter or what the line is called because if it's just the letter then it is r if it is the name then its a plane intersect.

7 0
3 years ago
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A graph has time (years) on the x-axis and height (inches) on the y-axis. A line goes through points (2, 3) and (4, 6).
Natalija [7]

Answer:

A, C, and D

Step-by-step explanation:

The rate of change will simply be the slope of the line, which we can find by taking the change in y and dividing that by the change in x:

slope = \frac{6-3}{4-2} =\frac{3}{2}

Thus, the slope is 3/2 = 1.5.

Since the slope remains constant throughout the graph, we know that A is correct. In addition because the points 0, 2, 4, and 6 are on the graph, the rate of change between any of the two points will still be the constant 1.5, making C and D correct as well.

So, we can choose A, C, and D.

Hope this helps!

5 0
2 years ago
Read 2 more answers
Please follow the directions. Don't round immediate calculations.<br>Please try to get it right
marin [14]

Answer:

well without rounding <em>anything</em><em>,</em><em> </em><em>I</em><em> </em><em>got</em><em> </em><em>511.9999999992</em><em> </em><em>people</em><em> </em>

Step-by-step explanation:

so the ratio I used was 36 people for every 225 people( 225 because in total he asked 225 people) then I divided 3,200 into 225 to see how many times It would fit, the answer was 14.2222222222 then I multiplied that by 36 and my answer was 511.9999999992 people. I hope this helps, I tried to be as accurate as possible.

4 0
2 years ago
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
Which statement is always true?
Goshia [24]
I’m pretty sure A is true <3
6 0
2 years ago
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