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neonofarm [45]
2 years ago
6

What is the value of x in the equation 25x2 = 16. A. 5/4. B. 4. C. 4/5. D. 16/25

Mathematics
1 answer:
Sergeeva-Olga [200]2 years ago
6 0

Answer:

x = ⅘

Step-by-step explanation:

For clarity, exponents should be marked with a ^.  25x² can be written as 25x^2.

25x² = 16

divide both sides by the 25

x² = 16/25

take the square root of both sides

x = √(16/25) = √16/√25 = 4/5

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Given: KPST is a trapezoid, KP=ST, MN is a midsegment, MN=20, h=15, PS:KT=3:7 Find: KS and KP
lions [1.4K]

Answer:

Length of KS = 25 units and

Length of KP = 17 units.

Step-by-step explanation:

Given: KPST is a trapezoid, KP =ST, MN is a mid segment, h is the height =15

Also it is given that, MN = 20 , h = 15 and PS:KT = 3:7.

  • If two sides of the trapezoid are equal then, it is an isosceles trapezoid.
  • Mid-segment of a trapezoid is a line segment which connects the midpoints of the non-parallel sides.
  • A trapezoid mid segment connects the midpoints of two congruent sides of the trapezoid and is parallel to the pair of parallel sides.
  • Length of the mid segment is the sum of two bases divide by 2

Since, the length of Mid-segment MN = 20.

Also, it is given: PS:KT = 3:7

Let  PS = 3x and KT = 7x respectively.

then;

\frac{PS+KT}{2} = 20

\frac{3x+7x}{2} = 20

\frac{10x}{2} =20

On Simplify, we get;

5x =20

Divide both sides by 5 we get;

x =4

Then:

Length of base PS = 3x = 3(4) = 12 and Length of base KT = 7x = 7(4) = 28.

Now, In triangle PLK

Using Pythagoras theorem to find KP;

It is given here, PL =h =15 and KL= 8 {you can see in the figure as shown below};

KP^2= PL^2 + KL^2

KP^2 = 15^2+8^2 =225 +64 = 289

KP = \sqrt{289}

Simplify:

KP = 17

therefore, the length KP = 17 units

To, construct a line: Join K and S

Now, in triangle KRS

KR = KL +LR = 8 +12 =20 and SR = h= 15

Using Pythagoras theorem in KRS to find KS;

KS^2 = SR^2+KR^2

KS^2 = 15^2 + 20^2 = 225 + 400 = 625

KS = \sqrt{625}

On simplify:

KS = 25

Therefore, the length of KS is, 25 units.

4 0
2 years ago
X-2y=-26 x-y=-2 solution of systems equation
svp [43]
If we subtract the 2 equations we eliminate x:-

x - x - 2y - (-y) = -26--2
-y = -24 
 y = 24
Plug this into the first equation:-
x - 2(24) = -26
x = -26 + 48  = 22


Answer is x = 22 and y = 24
4 0
3 years ago
How many significant numbers in 34.6209
JulijaS [17]

Answer:

6

Step-by-step explanation:

5 0
2 years ago
If there are 4 trucks for every 5 animals, then how many trucks would there be if there were 20 animals?
mel-nik [20]
There would be 16 trucks if there was 20 animals
7 0
2 years ago
Read 2 more answers
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
3 years ago
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