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3 years ago

-2n - 40 <5(6 + n) + 7n

Mathematics

2 answers:

bekas [8.4K]3 years ago

8 0

Answer:

n>-5

Step-by-step explanation:

uranmaximum [27]3 years ago

4 0

Answer:

n > -5

Step-by-step explanation:

Step 1: Distribute

-2n - 40 < 5(6 + n) + 7n

-2n - 40 < 30 + 5n + 7n

Step 2: Combine Like Terms

-2n - 40 < 30 + 5n + 7n

-2n - 40 < 30 + 12n

Step 3: Add 2n to both sides

-2n - 40 + 2n < 30 + 12n + 2n

-40 < 30 + 14n

Step 4: Subtract 30 from both sides

-40 - 30 < 30 + 14n - 30

-70 / 14 < 14n / 14

-5 < n

Answer: n > -5

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Answer: Option 'd' is correct.

Step-by-step explanation:

Since we have given that

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3 years ago

Alex wrote the expanded form for the number 165.038 as "100 60 5 30 8." was he correct? if not, give the correct expanded form.

grin007 [14]

The expanded form for the number 165.038 is 100+60+5+0.03+0.008.

<h3>What is the expended form of decimal numbers?</h3>

Writing decimals in expanded form simply means writing each number according to its place value. This is done by multiplying each digit by its place value and adding them together. Let's look at an example: 2.435. In words, we would say this as two and four hundred thirty-five thousandths.

In the given question expended form 100+60+5+30+8 is wrong.

After decimal point the first digit is at the tenth place and second digit at the hundredth place and third is at the thousandth place and so on....

165.038 = 100+60+5+ $\frac{0}{10}$ + $\frac{3}{100}$ + $\frac{8}{1000}$

= 100+60+5+0.03+0.008

Hence, The correct expended form of the given number is 100+60+5+0.03+0.008.

To learn more about expended form from the given link:

brainly.com/question/603715

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1 year ago

You are having a conference call with the CEO of a paper company. You have interpreted the number of trees cut down versus profi

loris [4]

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8 0

3 years ago

Read 2 more answers

Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat

likoan [24]

F+G:

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Then, add the elements that occupy the same position: