An inequality of the form
|X| < k,
where X is an expression in x, and k is a non-negative number, is solved by solving the following inequality
-k < X - k
You are given
|s| <= 2
Follow the pattern above to get
-2 <= s <= 2
In interval notation, the answer is
[-2, 2]
q = quarters
dimes is 3 plus 3times quarters
so 3q is 3 times quarters
so 3q+3 would be 3 times plus 3
equation is 3q+3
the value would be 10(3q+3)
Answer:
mass of mangos = 300g
mass of apples = 200g
mass of pears = 150g
Step-by-step explanation:
lets first reduce the ratio
12:8:6
is the same as
6:4:3
this means the the denominator of our fractions will be 6 + 4 + 3 = 13
hence
mangos = 6/13 of 650g
6/13 * 650 = 300
apples = 4/13 of 650g
4/13 * 650 = 200
pears = 3/13 of 650g
3/13 * 650 = 150
Answer:
The values of p in the equation are 0 and 6
Step-by-step explanation:
First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p
2
−7p−4=(2p+1)(p−4)
So then the equation looks like:
\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}
2p+1
p
−
(2p+1)(p−4)
2p
2
+5
=−
p−4
5
To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:
\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}
(2p+1)(p−4)
p
2
−4p
−
(2p+1)(p−4)
2p
2
+5
=−
(p−4)(2p+1)
10p+5
Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.
(p^2-4p)-(2p^2+5)=-(10p+5)(p
2
−4p)−(2p
2
+5)=−(10p+5)
Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p
2
−4p)−(2p
2
+5) first:
(p^2-4p)-(2p^2+5)=-p^2-4p-5(p
2
−4p)−(2p
2
+5)=−p
2
−4p−5
-p^2-4p-5=-10p+5−p
2
−4p−5=−10p+5
Combine like terms:
-p^2-4p+0=-10p−p
2
−4p+0=−10p
-p^2+6p=0−p
2
+6p=0
Factor:
p=0, p=6p
