9514 1404 393
Answer:
- domain: all real numbers, (-∞, ∞)
- range: all non-negative numbers, [0, ∞)
Step-by-step explanation:
There are no values of x for which this expression is undefined. The domain is all real numbers.
The minimum value of this expression is 0. There is no maximum value. The range is all numbers greater than or equal to zero.
Answer:
There's no answer choices but I can give you an example.
Step-by-step explanation:
- Let's say you have
. - Think about what the closest whole number 25/4 will give you. Since 24 and 25 are close you can do 24/4 and get 6.
- Now since you took one number away from the 25 you have a remainder.
- Since the denominator is 4 your final answer would be 6
.
Hopefully this helps.
I think the answer is 1
Explanation:2x+2=x+3
Subtract the 2 and the x from both sides
1x=1
Divide by one then you get 1
Answer:
Required center of mass 
Step-by-step explanation:
Given semcircles are,
whose radious are 1 and 4 respectively.
To find center of mass,
, let density at any point is
and distance from the origin is r be such that,
where k is a constant.
Mass of the lamina=m=
where A is the total region and D is curves.
then,

- Now, x-coordinate of center of mass is
. in polar coordinate 




![=3k\big[-\cos\theta\big]_{0}^{\pi}](https://tex.z-dn.net/?f=%3D3k%5Cbig%5B-%5Ccos%5Ctheta%5Cbig%5D_%7B0%7D%5E%7B%5Cpi%7D)
![=3k\big[-\cos\pi+\cos 0\big]](https://tex.z-dn.net/?f=%3D3k%5Cbig%5B-%5Ccos%5Cpi%2B%5Ccos%200%5Cbig%5D)

Then, 
- y-coordinate of center of mass is
. in polar coordinate 




![=3k\big[\sin\theta\big]_{0}^{\pi}](https://tex.z-dn.net/?f=%3D3k%5Cbig%5B%5Csin%5Ctheta%5Cbig%5D_%7B0%7D%5E%7B%5Cpi%7D)
![=3k\big[\sin\pi-\sin 0\big]](https://tex.z-dn.net/?f=%3D3k%5Cbig%5B%5Csin%5Cpi-%5Csin%200%5Cbig%5D)

Then, 
Hence center of mass 
Answer: Volume = 174.71 cubic meters
Step-by-step explanation:
Hi, to answer this, first, we have to apply the formula for the circumference (C) of a circle.
C= 2πr
Substituting with c=19.4 in the formula, and solving for the radius (r)
19.4= 2πr
19.4/ 2π =r
r= 3.09
Finally we apply the formula:
Volume of a right circular cone: 1/3 π r^2 h
Where h is the height of the cone and r is the radius of the base.
Replacing with the values given and calculated:
V=1/3 π (3.09)^2 (17.5)
V = 174.71 cubic meters