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sladkih [1.3K]
3 years ago
13

A methods and measurements analyst needs to develop a time standard for a certain task. In a preliminary study, he observed one

of his workers perform this task five times, with the following results: Observation 1 2 3 4 5 Time (Seconds) 84 76 80 84 76 What is the standard time for this task if the employee worked at a 25 percent faster pace than average and an allowance of 20 percent of job time is used?
Business
1 answer:
CaHeK987 [17]3 years ago
3 0

Answer:

120 seconds (2 minutes)

Explanation:

Standard time = normal time + allowances

The normal time is computed using the following formula

normal time = observed time X ratings/100

observed time mean = (84+76+80+84+76)/5 = 80

A person who is 25% faster has a rating of 125%

normal time = 80 X 125/100 = 100 seconds

Allowances is calculated as a percentage of normal time

Allowance = 80 X 20/100 = 20 seconds

Standard time = 100 + 20 = 120 seconds

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