Positive exponent? An index would imply that the base, x, had a fractional exponent.
My Dear Aunt Sally used to say, "If there's a negative exponent in your face, then flip your base!"
In other words, if the exponent is negative, take the reciprocal of the base, x →
and change the exponent to positive.
Therefore:
I have cross the fraction bar line change the exponent sign.
Answer:
-4/3
Step-by-step explanation:
the slope is -4/3
Answer:
Min. 1st Qu. Median Mean 3rd Qu. Max.
3.10 11.55 12.15 15.35 18.45 30.00
Step-by-step explanation:
The five-number summary includes five things that are:
1. Minimum Value
2. First Quartile (Q₁)
3. Median
4. Third Quartile (Q₃)
5. Maximum Value
So,
1. Minimum Value = 3.10
It can be found by arranging the data in ascending order, the first value we will get is the minimum value.
2. First Quartile is the middle value between Minimum value and Median of data after arranging data in ascending order.
First Quartile (Q₁) = 11.55
3. Median is the middle value of the data after arranging them in ascending order.
Median = 12.15
4. The third Quartile is the middle value between Median and Maximum Value of data after arranging data in ascending order.
Third Quartile (Q₃) = 18.45
5. Maximum Value is the largest value of the data or is the last value after arranging the data in ascending order.
Maximum Value = 30.
Percentiles are mostly use in very large data. Here n percent of data shows the nth percentile.
C major arc more than half the circle
Answer:
At 5% significance level, larger proportion of military personnel students protect their profiles on social-networking sites than young adults with profiles on social-networking sites.
Step-by-step explanation:
let p be the proportion of military personnel students who restrict access to their profiles. Then null and alternative hypotheses are:
: p=0.67 (67%)
: p>0.67
We need to calculate z-statistic of sample proportion:
z=
where
- p(s) is the sample proportion of military students who restrict access to their profiles (
=0.78)
- p is the proportion assumed under null hypothesis. (0.67)
- N is the sample size (100)
Then z=
≈ 2.34
The corresponding p-value is 0.0096. Since 0.0096<0.05 (significance level) we can reject the null hypothesis and conclude at 5% significance level that larger proportion of military personnel students protect their profiles on social-networking sites than young adults with profiles on social-networking sites.
