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Nonamiya [84]
3 years ago
8

A farmer can spend no more than $4,000 on fertilizer and seeds. The fertilizer costs $2 per pound and seeds cost $20 per pound.

To summarize the situation, the farmer writes the inequality: 2f + 20s ≤ 4,000, where f is the number of pounds of fertilizer and s is the number of pounds of seeds. Which graph's shaded region shows the possible combinations of fertilizer and seeds the farmer can buy?

Mathematics
2 answers:
lilavasa [31]3 years ago
7 0

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

f -----> the number of pounds of fertilizer

s ----> the number of pounds of seeds

we know that

The inequality that represent the situation is

2f+20s\leq 4,000

using a graphing tool

see the attached figure

The solution is the triangular shaded area

Dmitriy789 [7]3 years ago
4 0

Answer:

it is the 2nd graph

Step-by-step explanation:

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The graph of the sequence would have <br> (check image)
DanielleElmas [232]
<h3>Answer: D) common ratio</h3>

Explanation:

The four points on this curve are

(1, 3) ,  (2, 6),  (3, 12) ,  (4, 24)

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y = 3*2^(x-1) which is equivalent to y = 1.5*2^x

Both equations are exponential equations.

Sequences of the form

a(n) = a*(r)^(n-1)

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HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

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We can take 4n common

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= -3(4a +1)

7. 12n^5 + 16n^3

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4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

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11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

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13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

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Answer:

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Step-by-step explanation:

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Oksana_A [137]

Answer:

1 \frac{1}{6}

Step-by-step explanation:

\frac{3}{4}+ \frac{5}{12} =?\\

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

(\frac{3}{4} × \frac{3}{3} ) + (\frac{5}{12} ×\frac{1}{1})=?

Complete the multiplication and the equation becomes

\frac{9}{12} + \frac{5}{12}

The two fractions now have like denominators so you can add the numerators.

\frac{9+5}{12} = \frac{14}{12}

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 14 and 12 using

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The fraction

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Convert to a mixed number using

long division for 7 ÷ 6 = 1R1, so

7/6= 1 \frac{1}{6}

Therefore:

3/4 − (−5/12) = 1 \frac{1}{6}

Solution by Formulas

Apply the fractions formula for subtraction, to

3/4 − (−5/12)

and solve

(3×12) − (−5×4) 4×12

=3/6− (−20/48)

=56/48

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF( 56,48) = 8

56÷8 / 48÷8 =7/6

Convert to a mixed number using

long division for 7 ÷ 6 = 1R1, so

7/6= 1 \frac{1}{6}

Therefore:

3/4 − (-5/12) = 1 \frac{1}{6}

8 0
1 year ago
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