A farmer can spend no more than $4,000 on fertilizer and seeds. The fertilizer costs $2 per pound and seeds cost $20 per pound.
To summarize the situation, the farmer writes the inequality: 2f + 20s ≤ 4,000, where f is the number of pounds of fertilizer and s is the number of pounds of seeds. Which graph's shaded region shows the possible combinations of fertilizer and seeds the farmer can buy?
2 answers:
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Answer:
Step-by-step explanation:
To solve these equations involving variables and exponents we need to follow these steps.
1) We need to find out the factor that is common in the equation.
2) After taking common, solve the equation. We can add or subtract only those values that have same bases.
1)
here we can see, both numbers are divisible by 2, so taking 2 common
It cannot be further simplified because both number donot have same bases.
3.
We can take 4n common
5. -12a -3
Here -3 cam be taken common
= -3(-12a/-3 -3/-3)
= -3(4a +1)
7.
here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common
9.
Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common
11.
Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common
13.
Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common
15.
Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common
17.
Answer:
Step-by-step explanation:
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
×
+
×
Complete the multiplication and the equation becomes
The two fractions now have like denominators so you can add the numerators.
This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 14 and 12 using
GCF(14,12) = 2
14÷2 / 12÷2 =7/6
The fraction
7/6
is the same as
7÷6
Convert to a mixed number using
long division for 7 ÷ 6 = 1R1, so
7/6=
Therefore:
3/4 − (−5/12) =
Solution by Formulas
Apply the fractions formula for subtraction, to
3/4 − (−5/12)
and solve
(3×12) − (−5×4) 4×12
=3/6− (−20/48)
=56/48
Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF( 56,48) = 8
56÷8 / 48÷8 =7/6
Convert to a mixed number using
long division for 7 ÷ 6 = 1R1, so
7/6=
Therefore:
3/4 − (-5/12) =