Let's have Steve's age be <em>x</em><em />, and his father's age be <em>f</em>
Then, we can set up equations
Steve is one-fourth as old as his father goes to an equation as x=(1/4)f
In five years (x+5), Steve will be one-third as old as his father will be (f+5). This goes to an equation as x+5=(1/3)(f+5)
We can then solve the first equation for either variable (I will be doing f), and plug it in for a system of equations.
x=(1/4)f
4x=f ← plug that in for f in the next equation
x+5 = (1/3)(4x+5) ← Solve this for x
3(x+5)=4x+5
3x+15=4x+5
3x+10=4x
10=1x
x=10
Therefore, Steve's age is 10. His father's age is <em>f=4x, </em>plug in 10 for x, and his father's age is 40
Hope this helps:)
(2x+5)(6x-1) I wanted to make sure you could understand it
The answer to this point. is to add then multiple. 1 year
There are 36 different possibilities for his lunch.
We can use the fundamental counting principal to solve this problem. We simply need to find the number of options for each part of the meal and multiply them.
Sandwich = 3
Snack = 3
Dessert = 2
Drink = 2
3 x 3 x 2 x 2 = 36
