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leonid [27]
3 years ago
10

Calculate the amount of paint needed to cover the following door:

Mathematics
1 answer:
love history [14]3 years ago
4 0

Answer:

Step-by-step explanation:

The door is shape is a combination of a rectangle and a semicircle with a square window.

Area of the door = Area of rectangle + area of a semi circle

Area of a rectangle = Length * Width (LW)

area of a semicircle = πr²/2 where r is the radius of the semi circle.

Given the length of the rectangle = 2m and its width = 1m

Area of rectangle = 2*1 = 2m²

Given the radius of the semicircle = 1/2 m

Area of the semi circle = π(0.5)²/2

= 0.25π/2

= 0.785/2

Area of the semicircle= 0.3925m²

Area of the door = 2+0.3925

Area of the door = 2.3925m²

Since we are not to paint the window, we will subtract the area of the window from the total area.

Area of the window = area of a square = 0.2*0.2

= 0.04m²

Area to be painted = Area of door - Area of the square

Area to be painted = 2.3925m² - 0.04m²

Area to be painted  = 2.3535m²

Note that there was no enough information for us to calculate the amount of paint needed but knowing the area of the part to be painted can guide us.

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Katie and her brother are both writing a report. Katie write 7/8 of her report and her brother wrote 3/7 of his report. What is
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Answer:

Answer is 25/56

Step-by-step explanation:

Given that

Katie and her brother are both writing a report. Katie write 7/8 of her report and her brother wrote 3/7 of his report

TO compare these two fractions we have to make both of them have the same denominator.

We find that as such the two fractions have denominators as 7 and 8 and hence Least common multiple is 56

LEt us make equivalent fractions

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If 9th term ofap is 99 and 99th term is 9 which term is zero<br>]​
Viktor [21]

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Step-by-step explanation:

The nth term of an AP is

a_{n} = a₁ + (n - 1)d

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Given a₉ = 99 and a₉₉ = 9 then

a₁ + 8d = 99 → (1)

a₁ + 98d = 9 → (2)

Subtract (1) from (2) term by term to eliminate a₁

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2 years ago
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