Answer:
There is a 50% probablity that it will land on 1. There is a 30% chance it will land on 5.
Step-by-step explanation:
Answer:
Function
Step-by-step explanation:
This is a function.
The rule of a function is that every input has one output.
What that means is that for every x value, there is only one y value.
You can test this with the vertical lines method. If you draw vertical lines through the function, each vertical line should only intersect with the graph at a single point. If it intersects at two, it is not a function.
Answer:
1. Reduce 3x2-6x-240 to x^2 - 2x - 80
2. Use " ^ " to indicate exponentiation
3. Factor x^2 - 2x - 80 using completing the
x^2 - 2x + 1^2 - 1^2 - 80
(x+1)^2 - 1 - 80
(x+1)^2 - 81
(x+1)^2 - 9^2 = (x+1-9)(x+1 +9), or (x-8)(x+10)
Final answer, with all factors shown: 3(x-8)(x+10)
Step-by-step explanation:
Answer:
Remember that:
Speed = distance/time.
Then we can calculate the average speed in any segment,
Let's make a model where the average speed at t = t0 can be calculated as:
AS(t0) = (y(b) - y(a))/(b - a)
Where b is the next value of t0, and a is the previous value of t0. This is because t0 is the middle point in this segment.
Then:
if t0 = 100s
AS(100s) = (400ft - 0ft)/(200s - 0s) = 2ft/s
if t0 = 200s
AS(200s) = (1360ft - 50ft)/(300s - 100s) = 6.55 ft/s
if t0 = 300s
AS(300s) = (3200ft - 400ft)/(400s - 200s) = 14ft/s
if t0 = 400s
AS(400s) = (6250s - 1360s)/(500s - 300s) = 24.45 ft/s
So for the given options, t = 400s is the one where the velocity seems to be the biggest.
And this has a lot of sense, because while the distance between the values of time is constant (is always 100 seconds) we can see that the difference between consecutive values of y(t) is increasing.
Then we can conclude that the rocket is accelerating upwards, then as larger is the value of t, bigger will be the average velocity at that point.