V = lhr
V ÷ lh = lhr ÷ lh
V/lh = r
r = V/lh
Just divide both sides by what you want removed, leaving behind r.
The sqrt of 19 is between 4.3 and 4.4.
The sqrt of 18 is between 4.2 and 4.3.
The sqrt of 22 is between 4.6 and 4.7.
And finally, the sqrt of 21 is between 4.5 and 4.6.
I will give two solutions, one where everything is cubed and one where just the 3 is cubed, because I don't know what you meant.
Just the 3 is cubed solution(Which I think is correct because it has a nicer answer):
Answer:
Step-by-step explanation:
We have that 
.
We can subtract 
from both sides of the equation to get 
.
We can then divide by 
to get 
.
So, 
and we're done!
Everything is cubed solution:
Answer:
![\sqrt[3]{5}-3/2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%7D-3%2F2)
Step-by-step explanation:
We have that 
.
We can take the cube root of both sides to get ![2x+3=\sqrt[3]{40}](https://tex.z-dn.net/?f=2x%2B3%3D%5Csqrt%5B3%5D%7B40%7D)
.
Note that 
, so ![\sqrt[3]{40}=\sqrt[3]{2^3*5}=2\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B40%7D%3D%5Csqrt%5B3%5D%7B2%5E3%2A5%7D%3D2%5Csqrt%5B3%5D%7B5%7D)
.
So, we want to solve ![2x+3=2\sqrt[3]{5}](https://tex.z-dn.net/?f=2x%2B3%3D2%5Csqrt%5B3%5D%7B5%7D)
.
We can subtract 
from both sides to get ![2x=2\sqrt[3]{5}-3](https://tex.z-dn.net/?f=2x%3D2%5Csqrt%5B3%5D%7B5%7D-3)
.
We can then divide both sides by to get ![x=\sqrt[3]{5}-3/2](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%7D-3%2F2)
.
So, ![\boxed{x=\sqrt[3]{5}-3/2}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D%5Csqrt%5B3%5D%7B5%7D-3%2F2%7D)
and we're done!
Answer:
Lisa is 23 years old.
Step-by-step explanation:
36 (total) - 13 (brothers age) = 23 (Lisa's age)
23+13=36
If the unit you’re doing is similar polygons/triangles, then the tree is 19.5 ft tall. *** I’m from Canada so I’m not quite sure what a yardstick is but I’m assuming it’s a yard which is 3 ft so that’s what I used in my calculations lol
