Solution :
It is given that a psychologist wants to determine the difficulty of the task influences on the estimate of how long people spend working on it.
Now we have to describe a experiment by using a completely randomized design and learn the effect of the difficulty on the estimated time is by randomly assigning 15 students to a Group 1 of easy mazes and other 15 students to the second group 2 of hard mazes. And then we compare the time estimates of the two groups.
Yes. The situation is defined by a linear function.
<u>Solution:</u>
Given, The weekly salary of a store manager includes a $30 bonus plus the number of hours the manager works multiplied by the managers earnings per hour.
Is this situation defined by a linear function?
Yes, the above given situation is defined by a linear function.
Now, let us see the linear equation for above situation
Let the number of hours worked by manager be "x", and cost per hour be "c" and total salary be "y"
Then, total salary is given as,
Total salary = $ 30 bonus + number of hours worked
cost per hour

Above equation is a linear equation as "c" is constant ( cost per hour )
Hence, the given situation can be defined by linear function.
Answer:
324 minutes or 5 hours 24 minutes
Step-by-step explanation:
On Tuesday, Saima rode her bike for 52 miles. If it takes Saima 6 minutes to ride each mile, then it takes her

minutes to ride all 52 miles.
Before she rides her bike, Saima warms up for 12 minutes.
Therefore, it takes Saima

minutes to warm up and ride her bike on Tuesday.
ahaha good one
Step-by-step explanation:
...........

Here, we want to find the diagonal of the given solid
To do this, we need the appropriate triangle
Firstly, we need the diagonal of the base
To get this, we use Pythagoras' theorem for the base
The other measures are 6 mm and 8 mm
According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Let us have the diagonal as l
Mathematically;
![\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20l%5E2%3D6%5E2%2B8%5E2%20%5C%5C%20l%5E2%5Ctext%7B%20%3D%2036%20%2B%2064%7D%20%5C%5C%20l%5E2%5Ctext%7B%20%3D100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%2010%20mm%7D%20%5Cend%7Bgathered%7D)
Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above
Thus, we calculate this using the Pytthagoras' theorem as follows;