5/14+1/6=5*3/42+1*7/42=15/42+7/42=22/42=11/21
<h3>3+6-4.7-0(6)+1</h3><h3>=9-4.7-0+1</h3><h3>=9-4.7+1</h3><h3>=4.3+1</h3><h3>=5.3</h3>
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Answer:
a) The probability of falling in the warranty period is 11.6%.
b) The warranty period need to be 19771 km to ensure that no more than 5 per cent of tires fail in the warranty period.
Step-by-step explanation:
a) To fall within the warranty period, the tire has to fail before the 20,000 km.
To calculate the probability, we first calculate the z-value:

Then, the probability of falling in the warranty period is:

b) To calculate this we have to go on from a P(z<z₁)=0.05. This happens for z=-1.645.
This corresponds to a value X of:
The warranty period need to be 19771 km to ensure that no more than 5 per cent of tires fail in the warranty period.
Given (n)=-14
where (n-1) x 7 + 91
(-14) = -14