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Over [174]
3 years ago
13

Describe the relationship between n and 4 that will make the value of the expression 7 x n/4 fraction greater than 7?

Mathematics
2 answers:
Komok [63]3 years ago
7 0
I had this one in class. I'm in 5 the grade, and I don't know. I bet it is 3/4. I think. Hope it helps!!
Amanda [17]3 years ago
5 0
Its obvious that value of n that makes 7×n/4 greater than 7 belongs to interval ]7, infinity [
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What is the answer to the equation 5/14+1/6
BigorU [14]
5/14+1/6=5*3/42+1*7/42=15/42+7/42=22/42=11/21
3 0
3 years ago
3+6−4⋅7−0(6)+1 solve
igomit [66]
<h3>3+6-4.7-0(6)+1</h3><h3>=9-4.7-0+1</h3><h3>=9-4.7+1</h3><h3>=4.3+1</h3><h3>=5.3</h3>

please mark this answer as brainlist

7 0
3 years ago
(1) A manufacturer of tires believes that their mean time to failure (MTTF) is 20 613 km. They also believe that time to failure
ELEN [110]

Answer:

a) The probability of falling in the warranty period is 11.6%.

b) The warranty period need to be 19771 km to ensure that no more than 5 per cent of tires fail in the warranty period.

Step-by-step explanation:

a) To fall within the warranty period, the tire has to fail before the 20,000 km.

To calculate the probability, we first calculate the z-value:

z=\frac{X-\mu}{\sigma}=\frac{20000-20613}{512}=  \frac{-613}{512}= -1.197

Then, the probability of falling in the warranty period is:

P(X

b) To calculate this we have to go on from a P(z<z₁)=0.05. This happens for z=-1.645.

This corresponds to a value X of:

X=\mu+z*\sigma=20613+(-1.645)*512=20613-842=19771

The warranty period need to be 19771 km to ensure that no more than 5 per cent of tires fail in the warranty period.

5 0
3 years ago
SOLUTION IS REQUIRED TO UPLOAD AT THE END OF THIS FORM. NO SOLUTION, NO POINTS. Question: In the arithmetic sequence, 91, 84, 77
Dima020 [189]
Given (n)=-14
where (n-1) x 7 + 91
(-14) = -14
4 0
2 years ago
Which figure appears to show a line with a slope of 1?​
gulaghasi [49]

Answer:

I believe it is figure 1

7 0
3 years ago
Read 2 more answers
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