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cupoosta [38]
3 years ago
7

Which of the following correctly describes the end behavior of the polynomial function, f(x) 3x^4 +2x^2 -x? A. The left end goes

down and the right end goes up
B. Both ends go down.
C. Both ends go up.
D. The left end goes up and the right end goes down.
Mathematics
2 answers:
ozzi3 years ago
8 0
I think it’s A but I’m not 100%
kicyunya [14]3 years ago
8 0

Answer:

i think its 40

Step-by-step explanation:

i dont know though

You might be interested in
Solve the puzzle
wolverine [178]

Answer:

95891769

Step-by-step explanation:

This is extract from a brain teaser exercise in which sequence is formed to identify the numbers. In this brain teaser we have made combinations of different numbers which lead to the correct answer. The two correct forms of number are given which are used as a base for determining the correct answer.

4 0
3 years ago
Over the past month, a hairstylist has had 28 female clients and 12 male clients. What is the ratio of male clients to female cl
maw [93]

Answer:its A. 3/7 because it would be 12:28 so you'd simplify it.


Step-by-step explanation:

12/28=3/7

4 0
3 years ago
How do I solve this?
Tju [1.3M]

Answer:  A:  3x^2y^(3/2)

Step-by-step explanation:

This can be written as

(81*x^8*y^6)^(1/4)

Then multiply each exponent by (1/4):

81^(1/4)*x^(8(1/4))y^6(1/4))

81^(1/4) = 3

x^(8(1/4)) = x^2

y^6(1/4)) = y^(3/2)

The result:  3x^2y^(3/2)

7 0
2 years ago
Which of the following is the actual length of a window that is 1 1/4 inches long on a drawing with a scale of 1 inch =6 feet
DENIUS [597]
1.25/20=1x
1.25x=20
x=20/1.25=16
1 inch=16 feet
5 0
3 years ago
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 20%
zhuklara [117]

Answer:

a. 5% of the employees will experience lost-time accidents in both years

b. 24% of the employees will suffer at least one lost-time accident over the two-year period

Step-by-step explanation:

a. What percentage of the employees will experience lost-time accidents in both years?

20% last year, of those who suffered last year, 25% during this year. So

p = 0.2*0.25 = 0.05

5% of the employees will experience lost-time accidents in both years.

b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?

5% during the two years.

10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.

So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.

First year yes, not on the second.

75% of 20%. So, total:

0.05 + 0.05*0.8 + 0.75*0.2 = 0.24

24% of the employees will suffer at least one lost-time accident over the two-year period

3 0
3 years ago
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