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3 years ago

In Andrew Marvell's poem “To His Coy Mistress,” why does the speaker use the line “Thou by the Indian Ganges’ side”?

Advanced Placement (AP)

1 answer:

Xelga [282]3 years ago

5 0

Answer:

It is most definitely is not "To convey that his beloved seems far away"

Explanation:

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The text says that the American and British demand for unconditional surrender was actually a

seropon [69]

Answer:

Explanation:

The Second World War (WWII) was one of the major transformative events of the 20th century, with 39 million deaths in Europe alone.

Periods of hunger became more common even in relatively prosperous Western Europe.

Putting aside the very real human cost, war has also serious economic costs – loss of buildings, infrastructure, a decline in the working population, uncertainty, rise in debt and disruption to normal economic activity.

If wars alter long-term economic growth, they would permanently depress economic prospects of future generations so they had to surrender.

Mortality rate has reduced, lack of father to children and the war has cause severe hungers

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3 years ago

does anybody else just copy the questions on there homework and put them on here and hope they get an answer!!!

lora16 [44]

Answer:

yes

Explanation:

8 0

3 years ago

Read 2 more answers

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

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2 years ago

Are you worried about falling victim of a terrorist attack?if so,why not?

Natasha2012 [34]

It's really an opinion question from your perspective of terrorism.

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3 years ago

Alcohol, or any other drug which reduces the supply of oxygen in the bloodstream, can impair the sensitivity of the cones which,

Ahat [919]

Reduces the visual acuity or sharpness

Alcohol, or any other drug which reduces the supply of oxygen in the bloodstream, can impair the sensitivity of the cones which, in turn Reduces the visual acuity or sharpness.

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3 years ago

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