Answer:
Torque is 140.4 N-m.
Explanation:
Mass of the gymnast, m = 53 kg
Vertical force acting on the gymnast, F = 1080 N
Distance, r = 0.13 m behind the center of mass during a forward somersault. We need to find the torque generated about the center of mass. The force is acting behind the center of mass. F = -1080 N
Torque is given by :
So, the torque generated about the center of mass is 140.4 N-m.
Raising the hook, or load by exactly 1 meter, will allow the length of the compressed material regain its original length, provided it wasn't deformed by the 5% compression.
<h3>Hooke's law </h3>
Hooke's law states that the force applied to an elastic material is directly proportional to the extension of the material provided that the elastic limit of the material is not exceeded.
When the length of the material is compressed by 5%, the material will regain its original size and shape when the applied load is removed, if the material was not deformed by the compression.
Thus, raising the hook, or load by exactly 1 meter, will allow the length of the compressed material regain its original length, provided it wasn't deformed by the 5% compression.
Learn more about Hooke's law here: brainly.com/question/2648431
Answer: f = 927.55Hz
Explanation: Since the the tube is open-closed, the length of air and the wavelength of sound passing through the tube is given below
L = λ/4 where λ = wavelength.
speed of sound in air = v = 343m/s.
fundamental frequency of open closed tube = 315Hz
λ = 4L.
v = fλ
343 = 315 * 4L
343 = 1260 * L
L = 343/ 1260
L = 0.27m
In the same tube of length L = 0.27m but different medium ( helium), the speed of sound is 1010m/s.
The length of tube and wavelength are related by the formulae below
L = λ/4, λ=4L
λ = 4 * 0.27
λ = 1.087m.
v = fλ
1010 = f * 1.087
f = 1010/1.807
f = 927.55Hz
Answer: To help eliminate subjectivity
Explanation:
Edgenuity 2020
I think it’s A.1 like the first one