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nekit [7.7K]
3 years ago
12

In much the same way, the sun warms you by radiation on a clear day. The space between the sun and Earth has no air to transfer

thermal energy. Radiation is the transfer of energy by waves moving through space. Heat lamps used in restaurants are a familiar example of radiation.
Physics
1 answer:
Gennadij [26K]3 years ago
7 0

Answer:

What's the question?

Explanation:

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PLEASE HELP!!! WILL MARK BRAINLIEST!! Name and define the four fundamental forces.
alukav5142 [94]

Answer:

Gravity.The weak force. Electromagnetism.The strong force.

4 0
3 years ago
Read 2 more answers
Two forces act on the screw eye. If F = 600 N, determine the magnitude of the resultant force and the angle θ if the resultant f
kobusy [5.1K]

Answer:

how to solve this problem ???????

5 0
3 years ago
What average force is needed to accelerate a 9.20-gram pellet from rest to 125 m/s over a distance of 0.800 m along the barrel o
aleksklad [387]
Given:
u = 0, initial velocity
v = 125 m/s, final velocity
s = 0.0800 m, distance traveled
9.20 g, the mass of the pellet

If the acceleration is a, then
0² + 2*(a m/s²)*(0.800 m) = (125 m/s)²
1.6a = 15625
a = 9765.625 m/s²

Calculate the force.
F = (9.20 x 10⁻³ kg)*(9765.625 m/s²) = 98.84 N

Answer: 98.8 N (nearest tenth)
8 0
3 years ago
This procedure has been used to "weigh" astronauts in space: A 42.5 kg chair is attached to a spring and allowed to oscillate. W
Bingel [31]

Answer:

The mass of the astronaut is approximately 119.74 kg

Explanation:

Assuming this problem as a Simple Harmonic Motion of a mass-spring system, the period (T) of the oscillations for a mass (m) and spring constant (k) is:

T=2\pi\sqrt{\frac{m}{k}} (1)

First, we have to calculate the spring constant using equation (1) and the data provided for the oscillations without the astronaut:

<em>(it’s important to note that one complete vibration is the period of the movement)</em>

1.3=2\pi\sqrt{\frac{42.5}{k}}\Longrightarrow k=42.5(\frac{2\pi}{1.3})^{2}

k\approx992.8\,\frac{N}{m}

Now with the value of k, we can use again (1) to find the mass of the astronaut (Ma) that makes the period to be 2.54 seconds

2.54=2\pi\sqrt{\frac{42.5+M_{a}}{992.8}}\Longrightarrow M_{a}=992.8(\frac{2.54}{2\pi})^{2}-42.5

\mathbf{M_{a}\approx119.74\,kg}

3 0
3 years ago
A 10-m-long glider with a mass of 680 kg (including the passengers) is gliding horizontally through the air at 26 m/s when a 60
blagie [28]

Answer:

The glider’s speed after the skydiver lets go is 26 m/s

Explanation:

To calculate the glider’s speed just after the skydiver lets go, we will need to use the conservation of momentum

Mathematically;

mv = mv + mv

so 680 * 26 = (680-60)v + 60 * 26

17680 = 620v + 1560

17680-1560 = 620v

16120 = 620v

v = 16120/620

v = 26 m/s

4 0
3 years ago
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