Answer:
the correct one is D
Explanation:
The velocity of the center of mass of a body is
vcm = 1 / M sum mi vi
M = sum my
in this case we have two bodies
v_{cm} = 1 / m1 + m2 (m1 v1 + m² v2)
v_{cm} =
we can see that the velocity is an average between v₁ and v₂, but the exact value depends on the ratio of the masses of the bodies
when checking the answers the correct one is D
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 22 m/s
- Time (t) = 12 s
- Mass (m) = 200 Kg
- Let the acceleration be a.
- By using the equation of motion,
v = u + at, we have
- 22 m/s = 10 m/s + 12 s × a
- or, 22m/s - 10 m/s = 12 s × a
- or, 12 m/s = 12 s × a
- or, a = 1 m/s^2
- Let the force be F.
- We know, F = ma
- Therefore, the force on the accelerated object (F)
- = ma
- = (200 × 1) N
- = 200 N
<u>Answer</u><u>:</u>
<u>b)</u><u> </u><u>2</u><u>0</u><u>0</u><u> </u><u>N</u>
Hope you could understand.
If you have any query, feel free to ask.
The average speed is the distance (a scalar quantity) per time ratio. Speed is ignorant of direction. On the other hand, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes.
P=m/v
p=(292.2-130.2)/200
p=0.8100g/ml
In order to calculate velocity, we'd need to know the straight-line distance between the start and the finish, and we'd also need the direction of that line. The best we can do with the information given in the question is calculate the average SPEED.
Average speed = (total distance covered) / (time to cover the distance).
Distance covered in the first 2 hours = (2 hr) x (40 km/hr) = 80 km.
Distance covered in the second 2 hours = (2 hr) x (60 km/hr) = 120 km.
Total distance covered = (80 + 120) = 200 km
Time to cover the distance = (2 + 2) = 4 hours
Average speed = (200 km) / (4 hours) = 50 km/hour