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sleet_krkn [62]
3 years ago
5

What type of electricity comes from an outlet​

Physics
1 answer:
zalisa [80]3 years ago
8 0
There’s many types of electricity that comes from an outlet, like [15A, 120 Volt Outlets] those are more common in older homes and can come in two versions [Two-pronged outlet and three-pronged version]
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We say that visible light has wavelength from 400nm to roughly 800nm. What is the biggest "energy-jump" (excited) for an atom if
icang [17]

Answer:

4.98\cdot 10^{-19} J

Explanation:

The energy of the emitted photon is inversely proportional to its wavelength, according to the equation:

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34} Js is the Planck's constant

c=3.0\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

This means that the biggest energy is released when the wavelength is the shortest. For a photon of visible light, the shortest wavelength is

\lambda=400 nm = 400\cdot 10^{-9} m

So, substituting into the equation, we find the corresponding energy:

E=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{400\cdot 10^{-9}}=4.98\cdot 10^{-19} J

6 0
4 years ago
During which type of collision do the two objects stick together?
inysia [295]

Answer:

D. Perfectly inelastic

Explanation:

Kinetic energy is lost so the two bodies stick together.

6 0
3 years ago
A small car and a large bus have the same kinetic energy, which is traveling faster?
juin [17]
C same speed







it is the same speed
8 0
3 years ago
Read 2 more answers
Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g
Ne4ueva [31]

Answer:

C

Explanation:

- Let acceleration due to gravity @ massive planet be a = 30 m/s^2

- Let acceleration due to gravity @ earth be g = 30 m/s^2

Solution:

- The average time taken for the ball to cover a distance h from chin to ground with acceleration a on massive planet is:

                                 t = v / a

                                 t = v / 30

- The average time taken for the ball to cover a distance h from chin to ground with acceleration g on earth is:

                                 t = v / g

                                 t = v / 9.81

- Hence, we can see the average time taken by the ball on massive planet is less than that on earth to reach back to its initial position. Hence, option C

7 0
3 years ago
Calculate the tension on the rope.<br> A. 57.89 N<br> B. 32.73 N<br> C. 69.84 N<br> D. 12.55 N
Ratling [72]

Hi there!

\large\boxed{\text{B. 32.73N}}

To calculate the tension, we must calculate the acceleration of the system.

Begin with a summation of forces:

∑F = -M₁gsinФ + T - T + M₂g

Simplify and solve for acceleration: (Tensions cancel out)

a = \frac{-M_1gsin\theta + T - T + M_2g}{M_1+M_2}

Plug in values. Let g = 10 m/s²

a = \frac{-3(10)(sin30)+8(10)}{3+8} = 5.91 m/s^{2}

Now, to find tension, let's sum up the forces acting on ONE block. For simplicity, we can look at the hanging block:

∑F = -T + W

ma = -T + W

Rearrange to solve for T:

T = W - ma

We know the acceleration, so plug in the values:

T = (8)(10) - (8)(5.91) = 32.73 N

3 0
3 years ago
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