Part A:
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
a = (Vf - Vi) / t
where a is acceleration,
Vf is final velocity,
Vi is initial velocity, and
t is time
Substituting,
a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
<em>ANSWER: 3 m/s²</em>
Part B:
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
F = m x a
where F is force,
m is mass, and
a is acceleration
Substituting,
F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N
<em>ANSWER: 240 N </em>
Part C:
The distance that the sprinter travel is calculated through the equation,
d = V₀t + 0.5at²
Substituting,
d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
d = 13.5 m
<em>ANSWER: d = 13.5 m</em>
Answer:11.59 J
Explanation:
Given
mass of Particle 
Initially Particle moves towards left 
Final velocity of Particle is towards Right 
According to Work Energy theorem
Work done by all the Forces=change in Kinetic Energy
Work done by Force
![W=\frac{69\times 10^{-3}}{2}\left [ 31^-25^2\right ]](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B69%5Ctimes%2010%5E%7B-3%7D%7D%7B2%7D%5Cleft%20%5B%2031%5E-25%5E2%5Cright%20%5D)
![W=\frac{69\times 10^{-3}}{2}\left [ 961-625\right ]](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B69%5Ctimes%2010%5E%7B-3%7D%7D%7B2%7D%5Cleft%20%5B%20961-625%5Cright%20%5D)

The answer is the north pole the southern limit would be the south pole. if right please mark brainlyest
Answer:
Zero gravity
Explanation:
Astronauts around the earth either in spaceship, a space station or on a space walk appear to be weightless because of the zero gravity in such environment.
Weight is a function of the mass and acceleration due to gravity a body has.
Weight = mass x acceleration due to gravity
In a place where acceleration due to gravity is 0, the weight would be zero and a person would appear to be weightless.