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musickatia [10]
3 years ago
12

A large man sits on a four-legged chair with his feet off the floor. The combined mass of the man and chair is 95.0 kg. If the c

hair legs are circular and have a radius of 0.500 cm at the bottom, what pressure does each leg exert on the floor?
Physics
1 answer:
Leto [7]3 years ago
7 0

Answer:

Pressure, P=29.6\times 10^5\ Pa

Explanation:

It is given that,

Combined mass of the man and the chair, m = 95 kg

Radius of the leg of chair, r = 0.5 cm = 0.005 m

A large man sits on a four-legged chair with his feet off the floor. The force acting per unit area is called the pressure exerted.

P=\dfrac{F}{A}

P=\dfrac{mg}{A}

Area of 4 legs, A = 4 A

P=\dfrac{mg}{4\pi r^2}

P=\dfrac{95\times 9.8}{4\pi (0.005)^2}

P=29.6\times 10^5\ Pa

So, the pressure each leg exert on the floor is 29.6\times 10^5\ Pa. Hence, this is the required solution.

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Which term is undefined?
tensa zangetsu [6.8K]

The term which is considered as being undefined is referred to as a point and is therefore denoted as option A in this context.

<h3>What is a Point?</h3>

This is defined as as small round mark written on a plane which signifies the position or location of a substance. This can also be seen as a dot and is also used to separate a group of numbers such as in the case of decimals etc.

It is referred to as being undefined alongside a plane, line etc as a result of it only being explained using specific examples and descriptions unlike a segment which can be viewed and understood easily when working on the parameter.

This is therefore the reason why a point is undefined and the most appropriate choice.

Read more about Point here brainly.com/question/17206319

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3 0
2 years ago
a trcuk weighs four times as much as a stationary car. if teh truck coasts into the car at 12 km/s and they stick toegther, what
Andrews [41]

Answer:

  v=9.6 km/s

Explanation:

Given that

The mass of the car =  m

The mass of the truck = 4 m

The velocity of the truck ,u= 12 km/s

The final velocity when they stick = v

If there is no any external force on the system  then the total linear momentum of the system will be conserve.

Pi = Pf

m x 0 + 4 m x 12 = (m + 4 m) x v

0 + 48 m = 5 m v

5  v  = 48

v=\dfrac{48}{5}\ km/s

v=9.6 km/s

Therefore the final velocity will be 9.6 km/s.

3 0
3 years ago
Two objects are made of the same material, but they have different masses and temperatures. If the objects are brought into ther
DIA [1.3K]

The smaller body will have greater temperature change.

<h3><u>Explanation</u>:</h3>

Temperature is defined as the degree of hotness or coldness of a body. The relationship of the temperature with heat is described as

Q =m c dT.

Where Q is the heat content

m is the mass of body

c is the specific heat of body

dT is the temperature change of body.

Here the bodies are made up of same substance, so specific heat is same. The mass of bigger body is M and smaller body is m.

So the temperature change of the body will be dependent on the mass of the body. Heat loss by one body will be equal to heat gained by the other.

So M dT1 = mdT2.

So, M/m = dT2 / dT1.

So the the smaller body will be suffering higher temperature change.

3 0
4 years ago
Lunar eclipse
vichka [17]

Answer:

Hey

Your answer would be

The moon is not visible

due to Earth's shadow=lunar eclipse

The sun is not visible due

to the moon=solar eclipse

The moon is on the side of

Earth opposite the sun=new moon

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4 0
3 years ago
A tank having a volume of 0.85 m 3 initially contains water as a two-phase liquid-vapor mixture at 260 o C and a quality of 0.7.
Keith_Richards [23]

Answer:=14,160 kJ

Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below

Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase

C MPa m^3/kg kJ/kg kJ/kg

1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture

2 260 4.689 0.0422 2599 2797 1 Saturated Vapor

The mass initially contained in the tank is m1 = V/v1

m1 =0.85 m^3 /0.02993 m^3 /kg

= 28.4 kg

The mass finally contained in the tank is

m2 =V2/v

= 0.85 m^3 /0.0422 m^3 /kg

= 20.14 kg

The heat transfer is then

Qcv = m2u2 − m1u1 − he(m2 − m1)

Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ

4 0
3 years ago
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