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bogdanovich [222]
3 years ago
15

Simplify (6x2 − 3 + 5x3) − (4x3 − 2x2 − 16). (1 point) a 2x3 − x2 + 21 b −2x3 + x2 − 21 c x3 + 8x2 + 13 d −x3 − 8x2 + 13

Mathematics
2 answers:
tatiyna3 years ago
4 0

Answer:

the answer is C.

Step-by-step explanation:

sattari [20]3 years ago
3 0

(6x^2-3+5x^3)-(4x^3-2x^2-16)\\\\=6x^2-3+5x^3-4x^3+2x^2+16\qquad\text{combine like terms}\\\\=(5x^3-4x^3)+(6x^2+2x^2)+(-3+16)\\\\=x^3+8x^2+13\to\boxed{c.}

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The three consecutive integers are 127, 128, 129
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The sum of two numbers is 19, and their difference is 55. What are the two numbers?
Vilka [71]

Answer:

37 and -18

Step-by-step explanation:

Let one number be x and other y

1 x + 1 y = 19 .............1

1 x -1 y = 55 .............2

Eliminate y

multiply (1)by 1

Multiply (2) by 1

1 x 1 y = 19

1 x + -1 y = 55

Add the two equations

2 x = 74

/ 2

x = 37

plug value of x in (1)

1 x + 1 y = 19

37 + 1 y = 19

1 y = 19 -37

1 y = -18

y = -18

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3 years ago
The price of a ring was decreased by 25% to £390. <br> What was the price before the decrease
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You will pay $292.5 for a item with original price of $390 when discounted 25%. In this example, if you buy an item at $390 with 25% discount, you will pay 390 - 97.5 = 292.5 dollars
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3 years ago
At Lincoln High School, 25% of the students play on a sports team, and 13% of students play on a sports team and take a music cl
vekshin1

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Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
In a chess club the probability that Shaun will beat Mike is 3/8 .
romanna [79]

Answer:

\frac{10}{56} = 0.1786 probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

In a chess club the probability that Shaun will beat Mike is 3/8.

So 1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8} probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So 1 - \frac{5}{7} = \frac{2}{7} probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786

\frac{10}{56} = 0.1786 probability that Shaun loses both games

3 0
3 years ago
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