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xz_007 [3.2K]
3 years ago
11

Can you please help me with the questions I will give you brainliest.

Mathematics
1 answer:
KiRa [710]3 years ago
8 0

Answer:

C the First page

Step-by-step explanation:

1) you input the 2 into the T So the equation would look like this

15+2.5*(times) 2

2) I'm not sure for the second

3) A because you are using the number given then multiplying.

1.58* times 5 = 7.5

But the starting number would be 1.5 sense that's  the first number given

No one report me please.

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1 gallon of batter is poured equally into 4 bowls . How many gallons of batter are in each bowl?
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Answer:

1/4 gallon or 1 quart

Step-by-step explanation:

4 quarts = 1 gallon

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Can you guys help me with this math questions
dimulka [17.4K]

Answer:

2)  $40 per shirt

3)  80/9 m = 8.9 m (nearest tenth)

Step-by-step explanation:

The first question has been answered here: brainly.com/question/27846862

------------------------------------------------------------------------------------------------------

<u>Question 2</u>

Given information:

  • Previous sales = 300 shirts at $20 each
  • For every $1 increase in price, the number of sales diminishes by 5

Let x = number of $1 increases

Let y = total revenue (in dollars)

From the given information:

  • Price change of shirt:  (20 + x)
  • Number of sales change:  (300 - 5x)

Therefore, we can create a <u>quadratic equation</u> with the given information:

\implies y = (20+x)(300-5x)

As we need to find the maximum amount of revenue, we need to find the vertex of y.  As the equation is already factored, the quickest way to do this is to the find the mid-point of the zeros (since a quadratic curve is symmetrical).

\begin{aligned}y & =0\\\implies (20+x)(300-5x) & =0\\\implies (20+x) & =0 \implies x=-20\\\implies (300-5x) & = 0 \implies x=60\end{aligned}

\textsf{Midpoint}=\dfrac{-20+60}{2}=20

Therefore, Sammy should have 20 $1 increases to maximize the revenue, so the new price will be:

\implies \$20 + 20 \times \$1 = \$40\: \sf per\:shirt

------------------------------------------------------------------------------------------------------

<u>Question 3</u>

Given information:

  • Bridge is modeled as a parabola
  • Width of bridge = 30 m
  • Max height of bridge = 10 m high (in the middle)

As the bridge is modeled as a parabola, and we have been given the width and height, we can create a quadratic equation using the vertex form.

Vertex form:  y=a(x-h)^2+k

where:

  • x is the horizontal distance of the bridge
  • y is the height of the bridge
  • (h, k) is the vertex
  • a is some constant

Middle of the bridge = 30 m ÷ 2 = 15 m

Max height of the bridge = 10 m

Therefore, the vertex of the parabola is (15, 10)

\implies y=a(x-15)^2+10

We know that when x = 0, y = 0.  Therefore, substitute these values into the equation and solve for a:

\implies 0=a(0-15)^2+10

\implies 0=225a+10

\implies 225a=-10

\implies a=-\dfrac{10}{225}

\implies a=-\dfrac{2}{45}

Therefore, the equation of the parabola is:

\implies y=-\dfrac{2}{45}(x-15)^2+10 \quad \quad \textsf{for }0\leq x\leq 30

The horizontal distance at 5 m right of the middle is:

\implies \dfrac{30}{2}+5=20\:\sf m

Therefore, to find the height at this point, input x=20 into the equation and solve for y:

\implies -\dfrac{2}{45}(20-15)^2+10=\dfrac{80}{9}\:\sf m

Therefore, the height of the bridge at 5 m to the right of the middle is:

\dfrac{80}{9}\:=8.9\: \sf m\:(nearest\:tenth)

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2 years ago
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9- 4+ 7 +3 = 15

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Use the cos rule

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Which is 16.99 degrees, which is 17 (option d)
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no

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