Answer:


Step-by-step explanation:
<h3>Question-1:</h3>
so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,
to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

to solve the equation can consider the quadratic formula given by

so let our a,b and c be -4.9,229 and 346 Thus substitute:

remove parentheses:

simplify square:

simplify multiplication:

simplify Substraction:

by simplifying we acquire:

since time can't be negative

hence,
at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs
<h3>Question-2:</h3>
to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

let a and b be -4.9 and 229 respectively thus substitute:

simplify which yields:

now plug in the maximum t to the function:

simplify:

hence,
about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?
1) (-7,2)
y=2, -x+4=11, -x=11-4=7, x=-7
2) (-3,4)
-x+2y=11
y=4, -x+8=11, -x=3, x=-3
3) (1,6)
-x+2y=11
y=6, -x+12=11,-x=-1, x=1
Answer:
Step-by-step explanation:
- x² - 16 = 0
- x² = 16
- x = √16
- x = ± 4
Answer:
I think it would be 3/4
Step-by-step explanation: