Answer: 0.05
Step-by-step explanation:
Let M = Event of getting an A in Marketing class.
S = Event of getting an A in Spanish class,
i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45
Required probability = P(neither M nor S)
= P(M'∩S')
= P(M∪S)' [∵P(A'∩B')=P(A∪B)']
=1- P(M∪S) [∵P(A')=1-P(A)]
= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]
= 1- (0.80+0.60-0.45)
= 1- 0.95
= 0.05
hence, the probability that Helen does not get an A in either class= 0.05
Answer:
y = 3
y = 5
(last answer choice)
Step-by-step explanation:
A system of equation is given in "x" and "y".
For it to have a solution, there should be a value for x and a value for "y".
There needs to be 2 values, one for x and another for y.
It doesn't matter if the values of x and y are same, but there needs to be one value of x and one value of y (if linear equations).
First one has a value of x = 5 and y = 3, so there are 2 values, one for x and another for y, distinct values. So it's okay.
The second one has 2 values for x and y, respectively. THey are same, doesn't matter. So, this one is okay as well.
The last one has NO VALUE for x and has 2 values for y. So, this one doesn't have a proper solution.
So, the last one of the choices shown has NO SOLUTION.
Answer:
Question 1: Option B
Question 2: Option A
Step-by-step explanation:
Question #1:
Options are:
10¹¹ = 100000000000
10¹⁴ = 100000000000000
10¹⁵ = 1000000000000000
10¹² = 1000000000000
The power that exceeds the given quantity would be:
10¹⁴ ⇒ There are more digits.
Question #2:
We have the following expression:
981 44/51 = 61*981+44/61 = 981.72
We have to 10³ = 1000
So, the correct option is 10³
Parent function:
units downwards
y =x ; shift 6
