The answer is f(x)=x²+2x when evaluated with -3 gives you the value of 3
Let's check all functions.
1. The function f(x)=x²<span>+2x when evaluated with 3 gives you the value of 3:
Evaluated with x means that</span> x = 3.
f(3) = 3² + 2 * 3 = 9 + 6 = 15
15 ≠ 3, so, this is not correct.
2. f(x)=x²<span>-3x when evaulated with -3 give you the value of 3
Evaluated with -3 means that x = -3.
(f-3) = (-3)</span>² - 3 * (-3) = 9 + 9 = 18
18 ≠ 3, so, this is not correct.
3. f(x)=x²<span>+2x when evaluated with -3 gives you the value of 3
</span> Evaluated with -3 means that x = -3.
f(-3) = (-3)² + 2 * (-3) = 9 - 6 = 3
3 = 3, so this is correct.
4. f(x)=x²-3x when evaluated with -3 gives you the value of 3
Evaluated with 3 means that x = 3.
f(3) = (3)² - 3 * 3 = 9 - 9 = 0
0 ≠ 3, so this is not correct.
Answer:
Step-by-step explanation:
-3(3/6) + 4(3/5)
-3(1/2) + 4(3/5)
-3/2 + 12/5
-15/10 + 24/10
9/10
So, we know that a^2 + b^2 = c^2. Right? That is called the Pythagorean Theorem.
In this case. We can say that 39 is a, 40 is b, and x is c.
NOTE: It doesn't really matter whether 39 is a or b. a & b are just the two legs of the right triangle.
So, if we say that 39 is a, 40 is b, and x is c. We can plug it into the Pythagorean Theorem.
39^2 + 40^2 = x^2
I'll let you take it from there.
