What is the center of (x+5)^{2}+(y-4)^{2}=121?

Mathematics

1 answer:

Inessa [10]3 years ago

6 0

Answer: (-5,4)

Step-by-step explanation:

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Explanation:
Step 1: Combine like terms 7x-2=9x-8
Step 2: Put all variables on one side and all numbers on the other 2x=6
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A simple random sample from a population with a normal distribution of 103 body temperatures has x overbarequals98.90degrees Upp

Shtirlitz [24]

Answer:

$98.90-1.984\frac{0.62}{\sqrt{103}}=96.98$

$98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82$

The 95% confidence interval would be given by (96.98;100.82)

Step-by-step explanation:

Information given

$\bar X=98.90$ represent the sample mean

$\mu$ population mean (variable of interest)

s=0.62 represent the sample standard deviation

n=103 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=103-1=102$

Since the Confidence is 0.95 or 95%, the significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value for this case would be $t_{\alpha/2}=1.984$