How to do 3 1/2 minus 2 5/7 with different denominations

A - f(2x) <br> B - 1/2f(x) <br> C - f(1/2x) <br> D - 2f(x)

Ulleksa [173]

Answer:

A: $f(2x)$

Step-by-step explanation:

In this case it can be seen that the x values are being affected by this transformation. This means that we should look for points on f and g with the same y value but different x values. However in this case it is hard to pinpoint easy coordinates to work with. This is where process of elimination can help. We know it cant be B or C because if the dilation ratio is outside the function, the y values would be affected. That leaves it to A or D. We can see that g has shrunk from the original function. Shrinking along the x-values can be notated by the reciprocal of the factor of shrinking. In this case it looks like it shrunk down to half of the originals size. If we take the reciprocal of a half we get 2. Therefore if we plug that in we get:

$f(2x)$

3 0

4 years ago

A radio station installs a vhf radio tower that stands 1500 ft

aleksley [76]

Whats the question u just told us some of the information

4 0

3 years ago

A doctor released the results of clinical trials for a vaccine to prevent a particular disease. In these clinical trials, 200,0

CaHeK987 [17]

Answer:

1) No, there is not enough evidence to support the claim that the vaccine was effective (P-value=0.104) .

The null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

being the subindex 1 for the experimental group and subindex 2 for the control group.

2) Test statistic z=-1.26

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the vaccine was effective.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

The significance level is 0.01.

The sample 1 (experimental group), of size n1=100000 has a proportion of p1=0.0002.

$p_1=X_1/n_1=21/100000=0.0002$

The sample 2 (control group), of size n2=100000 has a proportion of p2=0.0003.

$p_2=X_2/n_2=30/100000=0.0003$

The difference between proportions is (p1-p2)=-0.0001.

$p_d=p_1-p_2=0.0002-0.0003=-0.0001$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{21+30}{100000+100000}=\dfrac{51}{200000}=0.00026$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.00026*0.99974}{100000}+\dfrac{0.00026*0.99974}{100000}}\\\\\\s_{p1-p2}=\sqrt{0+0.0000000025}=\sqrt{0.0000000051}=0.000071$