Question

How many grams are there in a 29 grams of a 0.285M solution of 385ml

Answer 1

Answer: 266.055 g

Explanation:

We have the following data related to this unknown substance:

$grams-of-substance=29 g$ are the grams of substance

$molarity=0.285M$ is the molarity of the substance, given by the following formula:

$molarity=\frac{moles-of-solute}{Volume-of-solution-in-liters}$ (1)

In this case the volume of solution is $385 ml \frac{1L}{1000 mL}=0.385 L$

Finding the moles of solute:

$moles-of-solute=(0.285M)(0.385 L)$ (2)

$moles-of-solute=0.109 moles$ (3)

Now we have to convert this to grams by the following relation:

$\frac{grams-of-substance}{moles-of-substance}=\frac{molar-mass-substance-in-grams}{1 mole}$ (4)

Finding $molar-mass-substance-in-grams$:

$molar-mass-substance-in-grams=\frac{grams-of-substance}{moles-of-substance} 1 mole$ (5)

$molar-mass-substance-in-grams=\frac{29 g}{0.109} 1 mole$ (6)

$molar-mass-substance-in-grams=266.05 g$