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Scrat [10]
3 years ago
12

The daily production of carbon dioxide from an 880 MW coal-fired power plant is estimated to be 31,000 tons. A proposal has been

made to capture and sequester the CO2 at approximately 300 K and 140 atm. At these conditions, the specific volume of CO2 is estimated to be 0.012 m3/kg. What volume (m3) of CO2 would be collected during a one-year period?
Chemistry
1 answer:
miskamm [114]3 years ago
5 0

Answer:

1.3578\times 10^{8} m^3 volume of carbon dioxide gas would be collected during a one-year period.

Explanation:

Mass of carbon dioxide gas collected in a day = 31,000 Tonn

1 Tonn = 1000 kilogram

31,000 Tonn = 31,000\times 1000 kg=31,000,000 kg

Specific volume of the carbon dioxide gas = V_s

V_s=0.012 m^3/kg

Volume of carbon dioxide gas collected in a day = V

V=V_s\times 31,000,000 kg=0.012 m^3/kg\times 31,000,000

V=372,000 m^3

1 year = 365 days

Volume of carbon dioxide gas collected in a year = V'

V'=372,000\times 365 m^3=1.3578\times 10^{8} m^3

1.3578\times 10^{8} m^3 volume of carbon dioxide gas would be collected during a one-year period.

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NItrogen in air reacts at high temperature to form NO2 according to the reaction:
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Answer:

The correct answer is option E.

Explanation:

Structures for the reactants and products are given in an aimage ;

Number of double bonds in oxygen gas molecule = 1

Number of double bonds in nitro dioxide gas molecule = 1

Number of single bond in in nitro dioxide gas molecule = 1

Number of triple bonds in nitrogen gas molecule = 1

N_2+2O_2\rightarrow 2NO_2,\Delta H=?

\Delta H=[2 mol\times \Delta H_{f,NO_2}]-[1 mol\times \Delta H_{f,N_2}-2 mol\times \Delta H_{f,O_2}]

\Delta H_{f,NO_2}=33.18 kJ/mol

\Delta H_{f,N_2}=0 (pure element)

\Delta H_{f,O_2}=0 (pure element )

\Delta H=2 mol\times 33.18 kJ/mol=66.36kJ=15.86 kcal

The enthalpy of the given reaction is 15.86 kcal.

6 0
3 years ago
Consider a closed containing a solid in equilibrium with its vapor. The volume of the solid is much less than that of the contai
Furkat [3]

Answer:

Explanation:

check the attachment below

5 0
2 years ago
Which is the next logical step in balancing the given equation? 3CO(g) + Fe2O3(s) Fe(s) + 3CO2(g)
Elena-2011 [213]

I believe that the answer is A.

5 0
3 years ago
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Two hydrogen atoms collide in a head on collision and end up with zero kinetic energy. Each then emits a photon of 121.6 nm (n=2
Zinaida [17]

Explanation:

Expression for the kinetic energy is as follows.

         K.E = \frac{1}{2}mv^{2}

Now, total kinetic energy will be as follows.

    K.E = 2 \times \frac{1}{2}mv^{2} = m \times v^{2}

Since, this energy converts into electromagnetic radiation of wavelength 121.6 nm.

Relation between energy and photon is as follows.

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Thus, we can conclude that atoms were moving at a speed of 3.12 \times 10^{4} m/s before the collision.

8 0
3 years ago
What pressure (in atmospheres) does a gas exert when at 385 mm of Hg?
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To find out the pressure in atm. You must divide 385 by 760. So pressure in atmospheres equals 385/760.
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