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Mademuasel [1]
3 years ago
8

Which sequence represents the relationship between temperature and volume as explained by the kinetic-molecular

Chemistry
1 answer:
Mars2501 [29]3 years ago
8 0

Explanation:

The kinetic energy of a gas molecule is given by :

E=\dfrac{3}{2}kT\\\\\implies E\propto T

It means, whenever the temperature of gas is increased, its kinetic energy will increase and the space between the particles gets increase. So, the space in which particles can collide with each other increases i.e. its volume gets high.

Hence, the correct option is (A). "higher temperature more kinetic energy → more space between particles – higher volume".

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If you had excess chlorine, how many moles of of aluminum chloride could be produced from 11.0 g of aluminum
dlinn [17]

Answer: 0.407 moles of aluminum chloride could be produced from 11.0 g of aluminum.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of aluminium}=\frac{11.0g}{27g/mol}=0.407moles

2Al+3Cl_2\rightarrow 2AlCl_3  

According to stoichiometry :

Al is the limiting reagent as it limits the formation of product and Cl_2 is the excess reagent.

As 2 moles of Al give = 2 moles of AlCl_3

Thus moles of Al give =\frac{2}{2}\times 0.407=0.407moles  of AlCl_3

Thus 0.407 moles of aluminum chloride could be produced from 11.0 g of aluminum.

5 0
3 years ago
4. What coefficients need to be added to the following chemical reaction
KengaRu [80]

Hey there!

C₆H₁₄ + O₂ → CO₂ + H₂O

Balance H.

14 on the right, 2 on the left. Add a coefficient of 7 in front of H₂O.

C₆H₁₄ + O₂ → CO₂ + 7H₂O

Balance C.

6 on the left, 1 on the right. Add a coefficient of 6 in front of CO₂.

C₆H₁₄ + O₂ → 6CO₂ + 7H₂O

Balance O.

2 on the left, 12 on the right. Add a coefficient of 6 in front of O₂.

C₆H₁₄ + 6O₂ → 6CO₂ + 7H₂O

Our final balanced equation: C₆H₁₄ + 6O₂ → 6CO₂ + 7H₂O

Hope this helps!

6 0
3 years ago
A solution has [c6h5cooh] = 0.100 m and [ca(c6h5coo)2] = 0.200 m. ka = 6.3 × 10−5 for c6h5cooh. the solution volume is 5.00 l. w
Eddi Din [679]

6.8 is the pH of the solution after 10 ml of 5M NaOH is added.

Explanation:

Data given:

Molarity of C6H5CCOH = 0.100 M

molarity of ca(c6h5coo)2  = 0.2 M

Ka = 6.3 x 10^-5

first pH is calculated of the buffer solution

pH = pKa+ log 10 \frac{[A-]}{[HA]}

pKa = -log10[Ka]

pka = -log[6.3 x10^-5]

pKa = 4.200

putting the values to know pH of the buffer

pH = 4.200 + log 10 \frac{0.2}{0.1}

pH = 4.200 + 0.3

    pH  = 4.5 (when NaOH was not added, this is pH of buffer solution)

now the molarity of the solution is calculated after NaOH i.e Mbuffer is added

MbufferVbuffer = Mbase Vbase

putting the values in above equation:

Mbuffer = \frac{MbaseVbase}{Vbuffer}

             = \frac{5X10}{5000}

             = 0.01 M

molarity or [ A-] = 5M

pH =   pKa+ log 10 \frac{[A-]}{[HA]}

pH = 4.200 + log 10 \frac{5}{0.01}

pH = 4.200+ 2.69

pH = 6.8

4 0
3 years ago
Read 2 more answers
GIVING BRAINLY AND 20 POINTS
ipn [44]

Explanation:

frequency= velocity/ wavelength

= 340/1.36

=250

8 0
3 years ago
If you are playing pool and hit the cue ball at the stationary 8 ball, what should happen?
jolli1 [7]

Answer If a ball goes into a pocket and bounces back on to the playing surface, it is not considered pocketed. If it is the 8-ball, it is not a win. If it is the cue ball, it is not a scratch.

Explanation:

3 0
3 years ago
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