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Lynna [10]
3 years ago
8

How many times should she expect to roll a number that is greater that 4

Mathematics
2 answers:
laiz [17]3 years ago
8 0
Only 2/6 times would you expect to roll a number greater than 4 at any given roll
Marizza181 [45]3 years ago
4 0
On a standard die the probability would be 2/6
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1/5...
This question should be relatively easy for a high schooler...
 
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Which list correctly orders A, B, and C from least to greatest when A=-8, B = |-61, and C = 11|?
Katena32 [7]
The correct border is b a c.
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3 years ago
If h (x) = {(-2,3), (0,4), (1,6), (2, 9)}<br><br> then what set of values represent h-1 (x) ?
vfiekz [6]

Answer:

h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}

Step-by-step explanation:

Given: h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}

To find: h^{-1}(x)

Solution:

A relation is said to be a function if each and every element of the domain has a unique image in the co-domain.

Inverse of a function exist if it is both one to one and onto.

h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}

h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}

7 0
3 years ago
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Vsevolod [243]

Answer:

yes

Step-by-step explanation:

6 0
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Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

I=sen(t)-t.cos(t)+C

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

cos(t)=\sqrt{1-sen^2(t)}

Entonces:

cos(t)=\sqrt{1-x^2}

Devolviendo los cambios:

I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C

Es la respuesta correcta

7 0
3 years ago
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