Hello :
the nth term is : An =A1 × r^(n-1)
A1 = 1 r = 2.3 n = 5
A5 =1 × (2.3)^(5-1)=27.9841
So you would do
5×4×3= 60
and
5×4=20
so, for a 3 digit code there are 60 possibilities and for a 2 digit code there are 20 possibilities.
Answer:
3
Step-by-step explanation:
2x + 3 = -x + 12
subtract 3 from both sides
2x = - x + 9
add x to both sides
3x = 9
divide by 3
x = 3
