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Virty [35]
3 years ago
9

What is perimeter? What is area? How can you find the perimeters and areas of triangles, parallelograms, rectangles, squares, an

d trapezoids in the real world? How do you find the perimeters and areas of these figures when drawn in diagrams? How are these processes similar? How are they different?
Mathematics
1 answer:
marusya05 [52]3 years ago
3 0
The perimeter of a figure is the total distance around the edge of the figure. The area of a flat, or plane figure is the number of unit squares that can be contained within it. The unit square is usually some standard unit, like a square foot or a square inch. I don't really know the rest but I did the first two lol
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Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

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Round 66,681 to the nearest ten thousand
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Answer:

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Step-by-step explanation:

66,681 is closest to 70,000 rather than 60,000.

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leva [86]

Answer:

3. 2 or x=2

Step-by-step explanation:

I put your question into a math calculator and this was the answer. Good luck!

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GalinKa [24]

is it a multiple choice?

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Mackenzie read 64 pages in 8 days. She read the same number of pages each day. How many pages did she read on Tuesday?
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Answer: 8

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