Answer:
4033
Step-by-step explanation:
An easy way to solve this problem is to notice the numerator, 2017^4-2016^4 resembles the special product a^2 - b^2. In this case, 2017^4 is a^2 and 2016^4 is b^2. We can set up equations to solve for a and b:
a^2 = 2017^4
a = 2017^2
b^2 = 2016^4
b = 2016^2
Now, the special product a^2 - b^2 factors to (a + b)(a - b), so we can substitute that for the numerator:
<h3>

</h3>
We can notice that both the numerator and denominator contain 2017^2 + 2016^2, so we can divide by
which is just one, and will simplify the fraction to just:
2017^2 - 2016^2
This again is just the special product a^2 - b^2, but in this case a is 2017 and b is 2016. Using this we can factor it:
(2017 + 2016)(2017 - 2016)
And, without using a calculator, this is easy to simplify:
(4033)(1)
4033
Answer:
Hello! i don't see the underlined digit
Answer:
B
Step-by-step explanation:
![6^{\frac{1}{4} } b^{\frac{3}{4} }c^{\frac{1}{4} }\\\\=(6^1b^3c^1)^{\frac{1}{4} }\\\\=(6b^3c)^\frac{1}{4} \\\\=\sqrt[4]{6b^3c}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20b%5E%7B%5Cfrac%7B3%7D%7B4%7D%20%7Dc%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%5C%5C%5C%5C%3D%286%5E1b%5E3c%5E1%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%5C%5C%5C%5C%3D%286b%5E3c%29%5E%5Cfrac%7B1%7D%7B4%7D%20%5C%5C%5C%5C%3D%5Csqrt%5B4%5D%7B6b%5E3c%7D)
so answer is B
Answer:
non linear
Step-by-step explanation:
because it isn't solved yet. x needs its value to continue.
Im pretty sure that it would be 4 but not sure