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3 years ago

Elena's pet dog Jacky eats 1.25 lbs of dog food everyday. What would be the food intake of the dog in a week?

Mathematics

1 answer:

Evgen [1.6K]3 years ago

3 0

8.75 lbs.
1.25 x 7 = 8.75.

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化學製程中溫度的影響為研究化學製程中溫度對產量之影響，我們在 3 種溫度下各生產 3批產品，結果如下表。請建立 ANOVA 表。在 0.05 顯著水準檢定不同的溫度是否會影響平均產量。

fiasKO [112]

Answer:

Step-by-step explanation:

產品 1 14 20 13

產品 2 15 11 18

產品 3 12 15 16

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3 years ago

HELPPP 15 POINTS!!

yanalaym [24]

Answer:

Option C, 30

Step-by-step explanation:

Step 1: Identify how many people spent $200

There was only 30 people that spent $200

Answer: Option C, 30

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3 years ago

Commercial agents earn 5% of the cost of each product they sell. If an agent earns

kicyunya [14]

Based on the information the cost of the product is $40,000.

Given:

Percentage earn=5% or 0.05

Amount earned=$2,000

Let x represent the cost of the product

Hence:

Formulate

.05x = $2000

Divide both sides by .05

x=$2,000/.05

x=$40,000

Inconclusion the cost of the product is $40,000.

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5 0

2 years ago

Read 2 more answers

Make x the subject of y = 4x + 1 You may use the flowchart to help you if you wish. X y

Paha777 [63]

Step-by-step explanation:

y = 4x+1

y–1 = 4x

x = (y–1)/4

5 0

3 years ago

Find the solution of the initial value problem dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago