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2 years ago

If you roll a dice and flip a coin, what is the probability you will land on a number greater than 4 and a heads?

Mathematics

1 answer:

irinina [24]2 years ago

4 0

Answer:

you have a 7/12 chance

Step-by-step explanation:

The sample space has 12 elements:

T1, T2, T3, T4, T5, T6

H1, H2, H3, H4, H5, H6

(From a combinatorics perspective, there are 2 options for the coin and 6 for the die for a total of 2 * 6 = 12.)

There are 6 heads results and one tales result that has a 4 for a total of 7 possibilities that meet your criteria. That makes the probability 7 / 12.

here is the link for where i got my answer https://www.quora.com/If-you-flip-a-coin-and-roll-a-die-what-is-the-probability-the-coin-lands-heads-up-or-the-die-lands-showing-the-number-4

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Answer-

The lines are two coinciding lines or the same lines.

Solution-

The given line equations are

the first one,

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$\Rightarrow y+1=\dfrac{1}{5}(x+5)\\\\\Rightarrow 5y+5=x+5\\\\\Rightarrow 5y=x\\\\\Rightarrow x-5y=0$

As we know two line equations $A_1x+B_1y+C_1=0$ and $A_2x+B_2y+C_2=0$ will be,

Parallel if, $\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}$
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Intersect if, $\dfrac{A_1}{A_2}\neq \dfrac{B_1}{B_2}$

As here,

$\Rightarrow \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}$

$\Rightarrow \dfrac{1}{1}=\dfrac{-5}{-5}$

(C₁ and C₂ aren't considered as they are 0)

Therefore, the lines are two coinciding lines or the same lines.

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