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3 years ago

If you roll a dice and flip a coin, what is the probability you will land on a number greater than 4 and a heads?

Mathematics

1 answer:

irinina [24]3 years ago

4 0

Answer:

you have a 7/12 chance

Step-by-step explanation:

The sample space has 12 elements:

T1, T2, T3, T4, T5, T6

H1, H2, H3, H4, H5, H6

(From a combinatorics perspective, there are 2 options for the coin and 6 for the die for a total of 2 * 6 = 12.)

There are 6 heads results and one tales result that has a 4 for a total of 7 possibilities that meet your criteria. That makes the probability 7 / 12.

here is the link for where i got my answer https://www.quora.com/If-you-flip-a-coin-and-roll-a-die-what-is-the-probability-the-coin-lands-heads-up-or-the-die-lands-showing-the-number-4

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(5+3√2)² simplify the following

madam [21]

Answer:

$(5+3\sqrt{2} )^{2} =43+30\sqrt{2}$

≈85.43

Step-by-step explanation:

apply the binomial theorem to the square

$=(5)^{2} +2(5)(3\sqrt{2} )+(3\sqrt{2} )^{2}$

$=25+30\sqrt{2} +18\\$

$=43+30\sqrt{2}$

≈85.43

Hope this helps

3 0

2 years ago

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What is another way to write 300+20+5

kakasveta [241]

325 three hundred twenty-five

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3 years ago

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On Saturday Ricardo drank a total of 40 fluid ounces of water.If he drank''m''fluid ounces of water that morning,which equation

Varvara68 [4.7K]

Answer:

n = ( 40 - m )

Step-by-step explanation:

On a particular day, Ricardo drank a total of 40 fluid ounces of water.

If he drank m fluid ounces of water in the morning of that day, then the number of fluid ounces of water he drank the rest of the day is given by (40 - m) fluid ounces.

If n represents the number of fluid ounces water that he drank the rest of the day, then we can write the equation as

n = ( 40 - m )

Therefore, the above equation can be used to find n. (Answer)

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3 years ago

A group of 8 friends went to a movie matinee. They spent $20 on snacks . The total cost of their tickets and snacks was $76.

Andru [333]

8x would represent multiplying 8(people) times x(ticket cost) But you don't know how much the tickets cost per person so that's why it's x.

8x + 20 = 76
76-20=56
56÷8=7
x equals 7

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3 years ago

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1) find the equation of the line parallel to

In-s [12.5K]

Answer:

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

Solution:

1) find the equation of the line parallel to x-5y=6 and through (4,-2).

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

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3 years ago