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Fynjy0 [20]
3 years ago
9

Hellpp -4c - 9.6 +5c = 0

Mathematics
2 answers:
Komok [63]3 years ago
6 0

Answer:

c = 9.6

Step-by-step explanation:

Let's look at our equation; - 4c - 9.6 + 5c = 0. Now we need to collect the like terms which are -4c and 5c.

- 4c - 9.6 + 5c = 0

5c - 4c - 9.6 = 0

We get: c - 9.6 = 0

Now we will add 9.6 on each side to see what c is equal to.

c - 9.6 = 0

  +9.6    +9.6

c = 9.6

Yay! We got our answer! Nice job everyone!

Ray Of Light [21]3 years ago
4 0

Answer:

c =9.6

Step-by-step explanation:

-4c - 9.6 +5c = 0\\\\\mathrm{Group\:like\:terms}\\-4c+5c-9.6=0\\\\\mathrm{Add\:similar\:elements:}\:-4c+5c=c\\c-9.6=0\\\\\mathrm{Add\:}9.6\mathrm{\:to\:both\:sides}\\c-9.6+9.6=0+9.6\\\\Simplify\\c=9.6

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Plzz helppp it's due today​
juin [17]

Answer:

8

Step-by-step explanation:

use trig functions

2 sides and 1 angle given

Sides given

  • hypotenuse -> x
  • opposite side to 30˚ -> 4

Angle

  • 30˚

trig function associated with hyp and opp is sin

sin(x) = opp/hyp

substitute

sin 30˚ = 4/x

solve for x

0.5 = 4/x

0.5x = 4

x = 8

7 0
3 years ago
Read 2 more answers
Solve using the elimination method.
densk [106]
Sorry I dont know this answer
7 0
3 years ago
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Point T is the midpoint of JH. The coordinate of T is (0, 5) and the coordinate of J is (0, 2). The coordinate of H is:
aev [14]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&J&(~ 0 &,& 2~) 
%  (c,d)
&H&(~ x &,& y~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left(\cfrac{x+0}{2}~~,~~\cfrac{y+2}{2}  \right)=\stackrel{midpoint~T}{(0~,~5)}\implies 
\begin{cases}
\cfrac{x+0}{2}=0\\\\
\boxed{x=0}\\
------\\
\cfrac{y+2}{2}=5\\\\
y+2=10\\
\boxed{y=8}
\end{cases}
6 0
3 years ago
What is the 18th term of the arithmetic
Irina18 [472]

Answer:

J

-66

Step-by-step explanation:

a1 = 2

n = 18

d = - 4

a18  =  a1 + (n - 1) * d

a18 = 2 + (18 - 1)*(-4)

a18 = 2 + 17*-4

a18 = 2 - 68

a18 = -66

3 0
3 years ago
I need help once again.
muminat
The dimensions of the prism can be 2x, 2x+3 and x+6.

We first factor out the GCF of the trinomial.  The GCF of the coefficients is 2.  Each term has an x in common as well, so the GCF is 2x.

Factoring out the 2x, we have
2x(2x²+15x+18).

To factor the remaining trinomial, we find factors of 2*18=36 that sum to 15.  12*3 = 36 and 12+3 = 15.  We split up 15x into 12x and 3x:

2x(2x²+12x+3x+18)

Now we group together the first two terms in parentheses and the last two:
2x((2x²+12x)+(3x+18))

Factor out the GCF of the first group:
2x(2x(x+6)+(3x+18))

Factor out the GCF of the second group:
2x(2x(x+6)+3(x+6))

Factoring out what these have in common,
2x(x+6)(2x+3)
8 0
3 years ago
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