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miv72 [106K]
4 years ago
14

5y-6=3y-20 how do i solve this problem

Mathematics
2 answers:
Studentka2010 [4]4 years ago
8 0
Im guessing its asking what y equals, subtract 3y from each side, the result is 2y-6=-20, add six to each side to get 2y=-14, divide each side by 2, the answer is.....
Y= -7
rusak2 [61]4 years ago
7 0
Minus 3y both sides
2y-6=-20
add 6 to both sids
2y=-14
divide 2
y=-7
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Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a  statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

P(9

Recall Chebyshev's inequality that

P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\

Comparing with the Ii equation which is appropriate here we find that

\mu =14.5

Next what we find is

k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071

Thus from the given information we find that

\mu = 14.5\\\sigma = 5.071\\k = 1.084

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