The magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T
<h3>Magnetic field inside solenoid</h3>
The magnetic field inside the central area of the solenoid is given by B = μ₀ni where
- μ₀ = permeability of free space = 4π × 10⁻⁷ Tm/A,
- n = number of turns per unit length = 3,170 turns/m and
- i = current in solenoid = 6.7 A
Since B = μ₀ni
Substituting the values of the variables into the equation, we have
B = μ₀ni
B = 4π × 10⁻⁷ Tm/A × 3,170 turns/m × 6.7 A
B = 4π × 10⁻⁷ Tm/A × 21239 A-turns/m
B = 84956π × 10⁻⁷ T
B = 266897.15 × 10⁻⁷ T
B = 0.026689715 T
B ≅ 0.0267 T
So, the magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T
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Answer:
Okay buddy the answer is 63 because if you look at all the angles they are suppose to add up to 180 so with the line D and A the angles is 128 so the angle on the other side is 52 so 52 plus65 is 117 so then 180-117 is 63
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