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3 years ago

420 rounding to the nearest 10

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

5 0

420 rounded to the nearest ten would be 420

Firlakuza [10]3 years ago

4 0

If u mean 420 rounded to the nearest 10, then the answer is...

420

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Pls i need an answer now

Elena-2011 [213]

Answer:

Step-by-step explanation:

1. 5, 3.5, $\sqrt{9\\}$ , $-\frac{12}{5}$ , -7

2. 10, π ,3.1415, 0, -10

3. 1 $\frac{1}{2}$ , 1.44, 1.4(3), 1.(43), $\frac{7}{5}$

6 0

2 years ago

What is the formula for a trapezium

aleksklad [387]

A= (a+b/2) × h

Is the formula for a trapezoid

4 0

3 years ago

Is -2.875 > -2 7/8?

Thepotemich [5.8K]

Answer:

The left side

−

2.875

is not greater than the right side

−

2.875

, which means that the given statement is false.

False

Step-by-step explanation:

8 0

3 years ago

A local hamburger shop sold a combined total of hamburgers and cheeseburgers on Thursday. There were fewer cheeseburgers sold th

myrzilka [38]

Answer:

the number of hamburgers sold on Thursday were 325.

Step-by-step explanation:

The total number of hamburger and cheese burger is missing

i will replace it with any figure, you can replace it wit your given data and you will get the solution.

A local hamburger shop sold a combined total of 593 hamburgers and cheeseburgers on Thursday

There were 57 fewer cheeseburgers sold than hamburgers

How many hamburgers were sold on thursday

Let h be the number of hamburgers and c be the number of cheeseburgers.

Using this information we can set up two equation as:

$h+c=593\\c=h-57$

Now we need to solve these two equations to get the value of number of hamburgers. For that we use substitution method as shown below:

$h+h-57=593\\2h-57=593\\2h=650\\h=325$

Therefore, the number of hamburgers sold on Thursday were 325.

6 0

3 years ago

Jun has 120 meters of fencing to make a rectangular enclosure. She also wants to use some fencing to split the enclosure into tw

Tems11 [23]

Answer:

Lenght = 20m

Width = 30m

Step-by-step explanation:

Perimeter of a rectangular enclosure = 2(L+W)

Adding a length of the fence parallel to one side of the sudden to split the closure, the total is 2(L+W) + L = 120

Area of a rectangular closure = L*W

To find the dimension that would maximize the area solve for L and W.

2(L+W) + L = 120

2L + 2W + L = 120

3L + 2W = 120

2W = 120 - 3L

W = (120 - 3L)/2

Put the value of W into Area formula

A = L*W

A = L *(120 - 3L) /2

= L(60 - 1.5L)

= 60L - 1.5L^2

= -1.5L^2 + 60L

This is a quadratic equation. Compare to ax^2 + bx + c

L = -b/2a

a = -1.5, b= 60, c= 0

L = -60/2(-1.5)

= -60/-3

= 20m

Put L = 20 into the value of W

W = (120 - 3L) /2

W= (120 - 3*20) / 2

= (120 - 60)/2

= 60 / 2

= 30m

The dimensions are 20m by 30m

8 0

3 years ago