Question

3. A driver's path when diving off of a platform is given by h(t)=-5t^2+10t+20, where h(t) is the distance above water, in feet, and t is the time from the beginning of the dive, in seconds.
3a. How high is the diving platform?
3b. After how many seconds is the diver 25 feet above water?
3c. When does the diver enter the water?

Answer 1

Answer:

3a.=20ft  3b.=1 second 3c.=3.25seconds

Step-by-step explanation:

Hello, Courtney!

h(t)=-5t^2+10t+20

20 would be the height so 3.a would be 20ft

3b.  25=-5t^2+10t+20

-5t^2+10t-5 then divide by greatest factor the answer would 1 second

3c.    0=-5t^2+10t+20 divide by greatest factor and would get 3.25 and -1.25 but can't have negative so the answer is 3.25.

I hope this helps

best you know who!