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anzhelika [568]
4 years ago
6

Liam and evan are mixing paint. Liam uses 2 quarts of yellow paint and adds 3 1/4 jars of blue paint. Evan uses 1/2 quart of yel

low paint and adds 5 1/2 jars of red paint. They end up with the same volume of paint. Write an equation to represent the situation.
Mathematics
1 answer:
Alina [70]4 years ago
3 0

Answer:

The required equation is given by,

2 + \frac {13x}{4} = \frac {1}{2} + \frac {11y}{2}

Step-by-step explanation:

Let, each jar of  Liam's paint contains x quarts of paint.

Then, Liam's solution contains,

2 + 3\dfrac {1}{4} \times x  quarts of paint  or,

2 + \frac {13x}{4} quarts of paint

and,

let, each jar of Evan's paint  contains, y quarts of paint.

Then, Evan's solution contains,

\frac {1}{2} + 5 \dfrac {1}{2} \times y quarts of paint or,

\frac {1}{2} + \frac {11y}{2} quarts of paint

now, according to the question,

the required equation is given by,

2 + \frac {13x}{4} = \frac {1}{2} + \frac {11y}{2}

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<span>1.       </span><span>Loan = 5000 dollars
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=> 8% = 8/100
=> .08
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=> In a year, there are 12 months, so that’s equals
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In a school, the ratio of musicians to athletes is 3 : 1. The number of musicians is how many times the number of athletes?  ANS
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Step-by-step explanation:


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What is the derivative of ln(lnx^3)
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the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

<u>Step-by-step explanation:</u>

Here we have to find the derivative of ln(lnx^3) , Let's find out:

We have , ln(lnx^3) , Let's differentiate it w.r.t x :

⇒ \frac{d(ln(lnx^3))}{dx}

Let lnx^3 = u

⇒ \frac{d(ln(u))}{dx}

⇒ \frac{1}{u} (\frac{d(u)}{dx} )

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Let x^3=v

⇒ \frac{1}{u} (\frac{d(ln(v))}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(v)}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(x^3)}{dx} )            

⇒ 3x^2(\frac{1}{u})(\frac{1}{v} )

Putting value of u & v we get:

⇒ 3x^2(\frac{1}{lnx^3})(\frac{1}{x^3} )

⇒ \frac{3}{x(lnx^3)}    { lnx^n = n(lnx)  }

⇒ \frac{3}{3x(lnx)}

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Therefore , the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

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