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3 years ago

Consider the graph of the exponential function, y =3(2)^x. The x- intercept of the graph is

Mathematics

1 answer:

Arisa [49]3 years ago

8 0

Answer:

the x intercept is 2

Step-by-step explanation:

I just went over this unit

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Pig 1 worked on his house 3 hours for a day for 10 days.How long did he work

WITCHER [35]

He worked 30 hours in total

3 0

3 years ago

Fill in the blanks to complete the area model to solve 6.60 divided by 15 is the same as _ x ? = _ 6.60 = _ hundredths

storchak [24]

Answer:

$15 x = 6.60$

$x = 44\ hundredths$

Step-by-step explanation:

Given

$\frac{6.60}{15}$

Required

Complete the model

[ ] x = 6.60

x = _ hundredths

$\frac{6.60}{15}$

Equate to x

$x = \frac{6.60}{15}$

Multiply both sides by 15

$15 * x = \frac{6.60}{15} * 15$

$15 * x = 6.60$

$15 x = 6.60$

So, we have:

[ ] x = 6.60 =====> $15 x = 6.60$

Recall that:

$x = \frac{6.60}{15}$

$x = 0.44$

This implies that:

$x = 44\ hundredths$

Hence:

x = _ hundredths =====> $x = 44\ hundredths$

3 0

3 years ago

PLEASE HELP

likoan [24]

Answer:

750

Step-by-step explanation:

https://brainly.in/question/5873877#:~:text=Hence%20750%20students%20are%20enrolled.

3 0

3 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

Compare the decimals 16.30 and 16.3

pshichka [43]

16.30 and 16.3 equal. If you ever have a problem like that then you just add on a zero.

Example:
19.4500 = 19.45 Just add two zeros on the end
19.45 + two zeros = 1.4500

8 0

3 years ago