1)100 or A
Angle = |30*H - (11/2)*M|, where H is the hours hand and M is the minutes hand
in this case: H = 4, M= 40
30*4 - (11/2)*40 = 120 - 220 = -100 = |-100| = 100
2)x=4y or C
If you plug in 0,0 you will get 0=4×0 or 0,0
(1+r)^5=137.76/100
1+r=(137.76/100)^(1/5)
R=(137.76/100)^(1/5))-1
Answer:
$8.2225
Step-by-step explanation:
100% - 45% = 55%
then divide 55 by 100 to get .55
lastly multiply .55 to 14.95 to get 8.2225
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
4(100)=400
400/1=400
You will need 400 stakes
