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2 years ago

What would be the distance traveled if you traveled 48 mph for 6 1/2 hours

Mathematics

2 answers:

nordsb [41]2 years ago

7 0

Answer: 312

Step-by-step explanation:

48 * 6= 288

Half of 48 is 24

24+ 288= 312

vichka [17]2 years ago

5 0

Answer:

312 m

Step-by-step explanation:

Speed = distance/time

6½ = 13/2

48 = distance ÷ (13/2)

Distance = 48 × 13/2

= 312

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A letter used to represent a number in equations or expressions

natita [175]

The answer is “x”. “x” represents the missing number in the problem.

Example:
16+x=20
The missing number, 4, would be represented as x. Hope this helps!

6 0

2 years ago

What is the product (4x)( -3x^6)(-7x^3)

11111nata11111 [884]

Answer:

84x^10

Step-by-step explanation:

The coefficients multiply, and the exponents add.

(4x)( -3x^6)(-7x^3) = (4)(-3)(-7)x^(1+6+3) = 84x^10

The rule for exponents is ...

(x^a)(x^b) = x^(a+b)

7 0

2 years ago

Help! This is due today and I'm stuck on this problem.

Varvara68 [4.7K]

Answer:

280.6 $m^2$

Step-by-step explanation:

<u>find the length of each side:</u>

you're only given h = 9 m

the formula for h is $h=\frac{\sqrt{3} }{2} *a$ , where a is a side length of the hexagon

plug h in:

$9=\frac{\sqrt{3}}{2}*a\\\\a=9*\frac{2}{\sqrt{3}}\\\\$

a ≈ 10.392 m

<u>now find the area of a triangle:</u>

1/2 (10.392)(9) = 46.764 $m^2$

multiply that by 6 and you get 280.584 ≈ 280.6 $m^2$

you can also use the regular hexagon area formula instead of finding the individual area and multiplying by 6: $\frac{3\sqrt{3} }{2} *a^2$

7 0

2 years ago

Read 2 more answers

A window in the shape of a rectangle as shown below has a width of x+5 and a length of x^2- 3x+7 express the area of the rectang

Ksju [112]

Answer:

$x^3+x^2-5x+28$

Step-by-step explanation:

since a=lw, the area is (x^2-3x+7)(x+4)

1. distribute parentheses $\left(x^2-3x+7\right)\left(x+4\right)=x^2x+x^2\cdot \:4+\left(-3x\right)x+\left(-3x\right)\cdot \:4+7x+7\cdot \:4$

2. apply +(-a)=-a rule $x^2x+4x^2-3xx-3\cdot \:4x+7x+7\cdot \:4$

3. Simplify

Steps to simplify:

$x^2x=x^3$

$3xx=3x^2$

$3\cdot \:4x=12x$

$7\cdot \:4=28$

$x^3+4x^2-3x^2-12x+7x+28$

4. Add like terms $=x^3+4x^2-3x^2-5x+28$

5. Add like terms $=x^3+x^2-5x+28$

6 0

2 years ago

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

2 years ago