3 years ago

Do two lines that are not parallel intersect

Mathematics

2 answers:

ad-work [718]3 years ago

5 0

Answer:

YESSS!!! 

HOPE IT HELPED

NARA [144]3 years ago

4 0

The answer to this Yes

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Quadratic equations are never used to solve word problems. True or false?

mel-nik [20]

Quadratic equations CAN be used to solve word problems so the answer to your question is false

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3 years ago

A bag contains 3 red marbles, 4 black marbles, and 5 yellow marbles. What are the chances of picking a marble that is not black?

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3 years ago

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Solve each system of equations by graphing Y=3x+4 and y=-x-4

In-s [12.5K]

Y = 3x + 4
y = -x - 4

3x + 4 = -x - 4
3x + x = -4 - 4
4x = -8
x = -8/4
x = -2

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3 years ago

The angle θ1\theta_1 θ 1 theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end

melomori [17]

Answer:

$\dfrac{3\sqrt{13}}{11}$

Step-by-step explanation:

Given that the angle $\theta_1$ is located in Quadrant II; and

$\cos(\theta_1)=-\dfrac{2}{11}$

In Quadrant II, x is negative and y is positive.

$\cos(\theta)=\dfrac{Adjacent}{Hypotenuse},\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Adjacent=-2\\Hypotenuse=11\\$

To find $\sin(\theta_1)$ , we first determine the opposite angle of $\theta_1$ .

This will be done using the Pythagoras theorem.

$Hypotenuse^2=Opposite^2+Adjacent^2\\11^2=Opposite^2+(-2)^2\\Opposite^2=121-4=117\\Opposite=\sqrt{117}=3\sqrt{13}$

Therefore:

$\sin(\theta_1)=\dfrac{Opposite}{Hypotenuse}=\dfrac{3\sqrt{13}}{11}$

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3 years ago

Use the function graphed on the coordinate plane below.

crimeas [40]

Answer:

Answer #3

Step-by-step explanation:

Also, this is Algebra 2, so it should be in the high school section.

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3 years ago