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2 years ago

11

Please help me with this problem

1 answer:

docker41 [41]2 years ago

5 0

Answer:

See below.

Step-by-step explanation:

The line segments AT and AS are perpendicular.

AT is equal in length to AS.

TM is perpendicular to SM.

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What is the following product?

morpeh [17]

Answer:

a

Step-by-step explanation:

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2 years ago

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PLZ ANSWER ASAP! THANKS

UNO [17]

$Log(\frac{M}{N}) = 4 \implies \frac{M}{N} = 10^4\\\\Log(\frac{P}{N}) = 5 \implies \frac{P}{N} = 10^5\\\\\implies P = 10M$

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3 years ago

Please helpppp!!!will mark brainlyist

user100 [1]

The answer is CB, AC, and AB

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2 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

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2 years ago

Abby scored 30 fewer points in the game than Charles scored. Abby scored 170 points in the game. Which equation can be used to c

zavuch27 [327]

C. 170=p-30,
can you mark me brainless

4 0

2 years ago

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