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Veronika [31]
3 years ago
6

Which system of equations could be graphed to solve the equation below? logo 5x = log32+ x

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

See below.

Step-by-step explanation:

I am assuming that the second part of the equation is log(32 + x).

Graph y = log 5x and y = log(32 + x).

The solution will be the point of intersection of the graphs.

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The sum of two numbers is eight one number is four less than the other find the numbers
mash [69]

Step-by-step explanation:

the numbers : x, y

x + y = 8

x = y - 4

we use the second equation in the first :

y - 4 + y = 8

2y - 4 = 8

2y = 12

y = 6

x = y - 4 = 6 - 4 = 2

4 0
2 years ago
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Find the length of the leg x of the right triangle shown below.
Alexus [3.1K]

Answer

9.327

16*16= 256

13*13=169

256-169=87

87 squared=9.32737905309

9.32737905309 ROUNDED TO NEAREST THOUSANDTH= 9.327

3 0
3 years ago
Which of the following methods can be used to find the derivative of y = arcsin x with respect to z ?
vfiekz [6]

Answer:

B) Ill only

Step-by-step explanation:

This is because y = arcsin x can be re-written as sin y = x, We then differentiate sin y = x implicitly with respect to z to obtain

d(siny)/dz = dx/dz

(cosy)dy/dz = dx/dz

dy/dz = (1/cosy)dx/dz

5 0
3 years ago
Given r(x) = 11/ (x - 42)
julsineya [31]

For a given function f(x) we define the domain restrictions as values of x that we can not use in our function. Also, for a function f(x) we define the inverse g(x) as a function such that:

g(f(x)) = x = f(g(x))

<u>The restriction is:</u>

x ≠ 4

<u>The inverse is:</u>

y = 4 + \sqrt{\frac{11}{x} }

Here our function is:

f(x) = \frac{11}{(x - 4)^2}

We know that we can not divide by zero, so the only restriction in this function will be the one that makes the denominator equal to zero.

(x - 4)^2 = 0

x - 4 = 0

x = 4

So the only value of x that we need to remove from the domain is x = 4.

To find the inverse we try with the general form:

g(x) = a + \sqrt{\frac{b}{x} }

Evaluating this in our function we get:

g(f(x)) = a + \sqrt{\frac{b}{f(x)} }  = a + \sqrt{\frac{b*(x - 4)^2}{11 }}\\\\g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4)

Remember that the thing above must be equal to x, so we get:

g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4) = x\\\\{\frac{b}{11 }} = 1\\{\frac{b}{11 }}*4 - a = 0

From the two above equations we find:

b = 11

a = 4

Thus the inverse equation is:

y = 4 + \sqrt{\frac{11}{x} }

If you want to learn more, you can read:

brainly.com/question/10300045

3 0
2 years ago
Select all TRUE statements : A - Dilation always increase the length of shapes or line segments. B- Dilations of an angle are co
timurjin [86]

Hi!

A is <u>FALSE</u> - If you shrink a shape, it is not increased a shape, yet it is still dilating.

B is <u>TRUE</u> - When you dilate an angle, you're really just shortening or lengthening the sides, but the angle isn't changing.

C is <u>FALSE</u> - Explained above.

D is <u>FALSE</u> - Two triangles that are congruent are <em>exactly the same, </em>therefore if you dilate a triangle, you are changing the size so they are not the same.

E is <u>TRUE</u> - Similar shapes are always the same <em>except for their size. </em>When you dilate a shape, you only change the size, therefore they are equal in every other way and they are similar.

6 0
2 years ago
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