The equation for a circle is (x-h)^2 +(y-k)^2=r^2
You just have to plug in your coordinates h is the x and k is the y.
The r is radius squared.
so, (x-2)^2+(y-(-5)^2=144
You have to be careful of those tricky negative values. When you distribute the y-(-5) it turns into y+5.
So your answer is D.
I think you can solve it by
=(x^2 - y^2) *( x^2 + y^2)
= (x -y)*(x+y)*(x^2 + y^2)
Answer:
<u>Given rhombus ABCD with</u>
- m∠EAD = 67°, CE = 5, DE = 12
<u>Properties of a rhombus:</u>
- All sides are congruent
- Diagonals are perpendicular
- Diagonals are angle bisectors
- Diagonals bisect each other
<u>Solution, considering the above properties</u>
- 1. m∠AED = 90°, as angle between diagonals
- 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
- 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
- 4. AE = CE = 5, as E is midpoint of AC
- 5. BE = DE = 12, as E is midpoint of BD
